getting only some values inside a string

[graziano]

Hello,

using ....

$freedisk = shell_exec (df -h | grep /usr);
echo $freedisk;

It returns me
/dev/sda2 2.0G 1.6G 310M 84% /usr

The problem is that on $freedisk I need only the percentuage (%) value 84%

Anyone can tell me a fast way to extract only 84% from
$freedisk ? Do I have to work with array or what ?

Thank you
Graziano

[OhLordy]

<?
//splits the string on the % symbol and puts the stuff either side in different elements of an array
$temp_array=explode('%',$freedisk);
//Does the same but on the [space] symbol
$temp_array_two=explode(' ',$temp_array[0]);
//takes the last element of temp_array_two and puts it in freedisk and adds a % on the end
$freedisk=$temp_array_two[(count($temp_array_two)-1)]."%";
?>

Hope this helps
Rob

[graziano]

Originally posted by OhLordy

<?
//splits the string on the % symbol and puts the stuff either side in different elements of an array
$temp_array=explode('%',$freedisk);
//Does the same but on the [space] symbol
$temp_array_two=explode(' ',$temp_array[0]);
//takes the last element of temp_array_two and puts it in freedisk and adds a % on the end
$freedisk=$temp_array_two[(count($temp_array_two)-1)]."%";
?>

Hope this helps
Rob [/B]

Thank you! Yes I understand (the solution is behind explode and
arrays .)

Meanwhile I found another solution myself ... (your solution is surely more fast 😉 !

<?

# find array
$systemoutput="/dev/sda2             2.0G  1.6G  310M  84% /usr";
$number = strlen($systemoutput); 

echo "systemoutput>>  $systemoutput <br>";
$array = explode(" ", $systemoutput); 

for ($findarray=0;$findarray<=$number;$findarray++){
# echo "Array > $findarray $array[$findarray] <br>";
if ( ereg("%",$array[$findarray])) {
$perc=$array[$findarray];
}

}

echo $perc;

?>