Php Logic Blues :) !!!!!!!

freebsd_dude

Hello Everyone,

I would like to round number off that end like the following:
Example:1

71.5 to be 72, Or something like t 71.4 to be 71.

I am not sure of the how to handle the math.

Second Part:

I have 11 Fields with numbers and i need to Calculate Avg's.

Example:2

13 | 43 | 45 | 0 | 22 | 33 | 11 | 88 | 99 | 10 | 21 | = only 10 because 0 isn't a number. But in a new field there could be

0 | 0 | 0 | 22 | 22 | 44 | 33 | 12 | 99 | 34 | 11 | = 8

11 | 11 | 33 | 44 | 32 | 44 | 32 | 11 | 99 | 21 | 87 = 11

So to make my avg add all the sums together and divide.

Thank You,

leatherback

Hi,

try:

http://www.phpbuilder.com/manual/function.round.php

for rounding.

As for the averaging: Not sure. How are the data ordered? In one big var, or in several individual var's? Always the same?

keith73

Originally posted by freebsd_dude
Hello Everyone,

I would like to round number off that end like the following:
Example:1

71.5 to be 72, Or something like t 71.4 to be 71.

I am not sure of the how to handle the math.

Second Part:

I have 11 Fields with numbers and i need to Calculate Avg's.

Example:2

13 | 43 | 45 | 0 | 22 | 33 | 11 | 88 | 99 | 10 | 21 | = only 10 because 0 isn't a number. But in a new field there could be

0 | 0 | 0 | 22 | 22 | 44 | 33 | 12 | 99 | 34 | 11 | = 8

11 | 11 | 33 | 44 | 32 | 44 | 32 | 11 | 99 | 21 | 87 = 11

So to make my avg add all the sums together and divide.

Thank You,

why only 10? If you have a list of numbers and you add them together then divide by the total #'s, you get a different answer if you take out the one's that are 0.

1+2+3 = 6 / 3 = 2
0+2+3 = 5 / 3 = 1.667
0+2+3 = 5 / 2 = 2.5

are these #'s in an array?
use a foreach loop to calculate the total #'s and the Sum.

to do it without using the 0's:

$sum = 0;
$num = 0;
foreach($numbers as $value){
	if($value > 0){
		$sum = $sum + $value;
		$num++;
	}
}//end foreach
$avg = $sum / $num;

to do it with the 0's, just take out the if statement.

keith

freebsd_dude

Hello,

How do i get to only add the 0+2+3 = 5 / 2 = 2.5

Example:
$date1 = 0
$date2 = 0
$date3 = 0
$date4 =11
$date5 =22
$date6 =33
$date7 =44
$date8 =5
$date9 =55
$date10 =1
$date11 =0

0+0+0+11+22+33+44+5+55+1+0 =171 / 7 24.42

Call me dumb but how do i use your example to code please!!!!

Thank you,
why only 10? If you have a list of numbers and you add them together then divide by the total #'s, you get a different answer if you take out the one's that are 0.

1+2+3 = 6 / 3 = 2
0+2+3 = 5 / 3 = 1.667
0+2+3 = 5 / 2 = 2.5

are these #'s in an array?
use a foreach loop to calculate the total #'s and the Sum.

to do it without using the 0's:

PHP:--------------------------------------------------------------------------------
$sum = 0;
$num = 0;
foreach($numbers as $value){
if($value > 0){
$sum = $sum + $value;
$num++;
}
}//end foreach
$avg = $sum / $num;

to do it with the 0's, just take out the if statement.

keith

leatherback

Hi,

How about something like:

$date = array($date1, $date2, $date3, $date4, $date5, $date6, $date7, $date8, $date9, $date10, $date11);

$sum = 0; 
$num = 0; 
foreach($date as $value)
{ 
if($value > 0) 
  { 
  $sum = $sum + $value;  

  $num++; 
  } 
}           //end foreach 

$avg = $sum / $num; 

echo $avg;