adding 0's in front of integers - easy one

chrisg101

Hi Guys,

Got a quick one for you. How do I quickly add zeros in front of an integer when displaying?
ie. Say I have the integer 2, but I need to display it as '002'. Do I do a quick float procedure or something with a precision of 3. I'm just guessing there. I checked the manual but nothing seemed obvious.

I just want to take the integer and when I'm displaying it (html) add zeros where appropriate.

Any help appreciated.
Thanks, Chris.

matt_4013

Hi Chris,

http://www.php.net/manual/en/function.str-pad.php

Hope that helps 🙂
Matt

Weedpacket

..or [man]sprintf/man to be hardcore about it.

suntra

More simple... (only for positive numbers)

<?
$int = 2;
if($int < 10) {
 $int = "00" . $int;
} else if($int < 100) {
 $int = "0" . $int;
}
?>

Weedpacket

Simpler still (only making sense for integers in the range [0,999]:

substr('00'.$number,-3);

matt_4013

str_pad($input, 3, "0", STR_PAD_LEFT);

C'mon, how can 6 lines of code be easier than that?

suntra

Again, it doesn't work with negative numbers...

<?
 $input = -1;
 echo str_pad($input, 3, "0", STR_PAD_LEFT);
?>

Will output: 0-1

But this :

<?
 $intNombre = -1;
 $intMultiple = 1;
 if($intNombre < 0) {
 	$intNombre *= -1;
 	$intMultiple = -1;
 }
 $strNombre = str_pad($intNombre, 3, "0", STR_PAD_LEFT);
 if($intMultiple == - 1) {
 	$strNombre = "-" . $strNombre;
 }
 echo $strNombre;
?>

will output: -001.

matt_4013

makes sense, good call 🙂

Weedpacket

Handles integers in the range [-999,999], padding them all to three digits.

echo sprintf(($n<0?'%04d':'%03d'),$n);