Why isn't this working?

[Bootsman123]

Does anybody knows why this isn't working? It just prints a white image of 6x6. The server has installed GD 2.0.

<?php
header ("Content-type: image/png");
$color = "#AFD61B";
$image = @imagecreate (6, 6) or die ("");
imagecolorallocate ($image, 255, 255, 255);
imageline ($image, 1, 1, 6, 1, $color);
imageline ($image, 1, 1, 1, 6, $color);
imageline ($image, 6, 1, 6, 6, $color);
imageline ($image, 1, 6, 6, 6, $color);
imagefilledrectangle  ($image, 3, 3, 4, 4, $color);
imagepng ($image);
imagedestroy ($image);
?>

[Mordecai]

Originally posted by Bootsman123

<?php
header ("Content-type: image/png");
$color = "#AFD61B";
$image = @imagecreate (6, 6) or die ("");
imagecolorallocate ($image, 255, 255, 255);
imageline ($image, 1, 1, 6, 1, $color);
imageline ($image, 1, 1, 1, 6, $color);
imageline ($image, 6, 1, 6, 6, $color);
imageline ($image, 1, 6, 6, 6, $color);
imagefilledrectangle  ($image, 3, 3, 4, 4, $color);
imagepng ($image);
imagedestroy ($image);
?>

[/B]

Okay, you need to allocate the colors you use in the images, rather than using the hex value. You'll need to use this code to get that color:
$color = imagecolorallocate($image,175,214,27);

If you want to use colors from hex values, you'll have to convert them from hex using hexdec():

$color = "AFD61B";
$r = hexdec(substr($color,0,2));
$g = hexdec(substr($color,2,4));
$b = hexdec(substr($color,4,6));
$coloral = imagecolorallocate($image,$r,$g,$b);

Keep in mind the first color you allocate is the background color.