Failed to create stream question

bcp1961

I'm trying to edit a sitemap creator so that it will get the <title> and <description> from the html's that it's indexing and use them for the hyperlink. (<title> as hyperlink, "description" as descriptive sentence.)

I don't know if I'm using the right code or if I'm even placing the code in the right part of the script. I am getting a message that says:
"Warning: get_meta_tags(index.html) [function.get-meta-tags]: failed to create stream: No such file or directory in /home/prescri/public_html/sitemap1.php on line 91"

Line 91 is where the "get_meta_tags" function is. Here's a little of the code, I'd really appreciate any help- I've been trying to figure this out for 4 days now...

                             $tags = get_meta_tags("$sfiles[$y]"); 
                             $title = $tags[title]; 
                             $descr = $tags[description]; 


                         { 
                         if(ereg("php$", $sfiles[$y]) && ($display == "both" || $display == "PHP")) 
                         { 
echo "<a href=http://$SERVER_NAME/$dir1/$sfiles[$y]>$title</a>- $descr</td></tr>"; 

                         } 

[code=php]

Please Help...
:confused: 
Thanks
Bernadette

kevinsequeira

is index.html ie the value at $sfiles[$y] in the same directory as sitemap1.php ???
if its not in the same directory you will have to use the full name to the page.

$url = "http://server/directory/".$sfiles[$y];
get_meta_tags($url);

$localfile = "/path_to_file/".$sfiles[$y];
get_meta_tags($localfile);
reg
kevin

bcp1961

Yes it's at the same level. This message runs through all the files on that same level and gives the same error message , just with a different file name ie. (index.html). Normally the script will create a site map for the entire domain, including all subdirectories, using the filename as the hyperlink. I am trying to get the script to use the <title> as the hyperlink, followed by the "description.

The $sfiles[$y] variable I believe represents all files located within the domain that are not pegged as being a directory or image- basically all the html, htm, php ect. files. Does that make sense? Do you need to see more of the code?
If you want to see the errors this is the url:
http://1prescription-drugs-info.com/sitemap2.php
The errors and scripts are for this page, I just had sitemap1.php open in my text editor at the time I sent the post, but it's the same code as sitemap2.php.

Thanks for your help!
Bernadette

kevinsequeira

could you post the code for the page ?

reg
kevin

Ivains

I've been trying to figure out how to do the same myself...

Here is the code:

$stime = gettimeofday();

/ some preliminaries... /
$root = getcwd();

$pre = explode("/", $REQUEST_URI);
array_pop($pre);
$prefix = join("/", $pre);

/ Uncomment the line below to create a tree of all files and directories on your webserver if the script
is in a subdirectory /
/ $root = str_replace($prefix, "", $root); */
$root .= "/";

/ Display server name and directory /
echo "<table cellspacing=0 cellpadding=0 border=0>\n";
echo "<tr><td><img align=absmiddle src=images/server.gif> [url]http://[/url]$SERVER_NAME";
if($root == getcwd()."/") { echo "$prefix/"; }
else { echo "/"; }
echo "</td></tr><tr><td><img align=absmiddle src=images/vertical.gif></td></tr>\n";

/ Recursion, here we go.. /
function list_dir($chdir)
{
/ some globals, some cleaning /
global $root, $display, $prefix, $PHP_SELF;
unset($sdirs);
unset($sfiles);
chdir($chdir);
$self = basename($PHP_SELF);
/ open current directory /
$handle = opendir('.');
/ read directory. If the item is a directory, place it in $sdirs, if it's a file of the type
php, htm, html or shtml and not this file, put it in $sfiles */
while ($file = readdir($handle))
{
if(is_dir($file) && $file != "." && $file != "..")
{ $sdirs[] = $file; }
elseif(is_file($file) && $file != "$self" && ereg("(php|htm|html|shtml)$", $file))
{ $sfiles[] = $file; }
}

/* count the slashes to determine how deep we're in the directory tree and how many
 * nice bars we need to add */
$dir = getcwd();
$dir1 = str_replace($root, "", $dir."/");
$count = substr_count($dir1, "/") + substr_count($dir1, "\\");



chdir($chdir);

/* iterate through the array of files and display them */
if(is_array($sfiles)) {
	sort($sfiles);
	reset($sfiles);

	if(!isset($display))
	{ $display = "both"; }

	$sizeof = sizeof($sfiles);

	/* what file types shall be displayed? */
	for($y=0; $y<$sizeof; $y++) {
		if(ereg("php$", $sfiles[$y]) && ($display == "both" || $display == "PHP")) {
			echo "<tr><td>";
			for($z=1; $z<=$count; $z++)
			{ echo "<img align=absmiddle src=images/vertical.gif>&nbsp;&nbsp;&nbsp;"; }
			if($y == ($sizeof -1))
			{ echo "<img align=absmiddle src=images/verhor1.gif>"; }
			else
			{ echo "<img align=absmiddle src=images/verhor.gif>"; }
			echo "<img align=absmiddle src=images/php.gif> ";
			echo "<a href=\"$prefix$dir1/$sfiles[$y]\">$sfiles[$y]</a></td></tr>";
		}
		elseif(ereg("(html|htm|shtml)$", $sfiles[$y]) && ($display == "both" || $display == "HTML")){
			echo "<tr><td>";
			for($z=1; $z<=$count; $z++)
			{ echo "<img align=absmiddle src=images/vertical.gif>&nbsp;&nbsp;&nbsp;"; }
			if($y == ($sizeof -1))
			{ echo "<img align=absmiddle src=images/verhor1.gif>"; }
			else
			{ echo "<img align=absmiddle src=images/verhor.gif>"; }
			echo "<img align=absmiddle src=images/html.gif> ";
			echo "<a href=\"$prefix$dir1/$sfiles[$y]\">$sfiles[$y]</a></td></tr>\n";
		}
	}
	echo "<tr><td>";
	for($z=1; $z<=$count; $z++)
	{ echo "<img align=absmiddle src=images/vertical.gif>&nbsp;&nbsp;&nbsp;"; }
	echo "</td></tr>\n"; 
}

}

list_dir($root);

echo "</table>\n";

Currently it displays the name of the file hyperlinked. Would like it to display the title name hyperlinked.

Any suggestions would be gratefully appreciated.

bcp1961

Here's a piece of code I recieved for this, still trying to work out the title part...

 if(ereg("php$", $sfiles[$y]) && ($display == "both" || $display == "PHP"))
							 {
								  echo "<tr><td>";
								  for($z=1; $z<=$count; $z++)
		  					 	  { echo "<img align=absmiddle src=vertical.gif>&nbsp;&nbsp;&nbsp;"; }
							 	  if($y == ($sizeof -1))
								  { echo "<img align=absmiddle src=verhor1.gif>"; }
								  else
								  { echo "<img align=absmiddle src=verhor.gif>"; }
								  echo "<img align=absmiddle src=php.gif> ";
								  $tags = get_meta_tags($dir."/".$sfiles[$y]); 
								$descr = $tags['description'];

Hope it helps
Bernadette