[Resolved] Array problems...

mo0ness

Hey all, I have an array..inside an array - and i basically wish to print the value of the assigned array variable...


$db = array('connect' =>
			 array('host'   => 'localhost',
				   'user'   => 'mo0ness',
				   'pass'   => 'my_pass',
				   'dbname' => 'fromesh')
			);

I tried doing:

print "$db[connect]['host']";

But all I get is "Array['host']" etc. Can any1 help me here and possibly correct me? Or is there a better way of doing what I wish to do? This content is inside a connection function, that when called; checks for a database connection. Thanx alot for ya time and any help 🙂

dbchip2000

Hi,
From your previous post

$db = array('connect' =>
            array('host'   => 'localhost',
                  'user'   => 'mo0ness',
                  'pass'   => 'my_pass',
                  'dbname' => 'fromesh')
           );

In your previous post you called the array variable by

$db[connect]['host']

 You should put the first key (connect) in quotes.  Otherwise I think it will be looking for an undefined variable.
 It worked when I tried it though, but PHP does not recommend that you not use strings unquoted.  Try it and see if it helps

ahundiak

PHP does not always do well when evaluating stuff inside of " marks. It has trouble with knowing what belongs to the variable and what is just stuff to be printed.

You can get around this with squiggly brackets.
print "{$db['connect']['host']}";

But it might be better to just not use the quotes at all.

print "Some Stuff " . $db['connect']['host'] . " Some more stuff";

dbchip2000

Sorry, I understand now...the problem was it was already in quotes. So when you told it to print, variables only go to the first key with that format making it print the variable type (Array) and then print the rest of what you typed ['host']. I always had wondered how to do it within quotes, but ahundiak just answered my question too

mo0ness

Thanks guys, it helped and everythings working fine now 🙂