Exit to last HTML blocks

rvgman05

I need help with this coding. See What I want to do is obtain a connection handler to a Mysql Database and see if that variable has the connection. If not then I display an Error message that the database is not available at that time. However if I just use a single if statement to check this condition and issue an exit command from that so that the rest of the code can be executed, there is still HTML code that I want to be shown. Here look at my example of what the code looks like.

<?
@ db = mysql_pconnect(...);
if (!db)
{
...Display Error
exit;
}
...Handle Database information
?>
...HTML CODE (THE CODE I WANT TO BE DISPLAYED)

So the Question is, is there a way to get the HTML CODE to be DISPLAYED without having to do this (use an if...else block):

<?
@ db = mysql_pconnect(...);
if (!db)
{
...Display Error
}
else
{
...Handle Database information
}
?>
...HTML CODE (THE CODE I WANT TO BE DISPLAYED)

Thanks for any help.
-rvgman05

sijis

hmm. that's a good question, to me at least.

i have 2 ideas, instead of using the exit; statement, use the continue; statement.. something like this:

<?
@ db = mysql_pconnect(...);
if (!db)
{
...Display Error
continue; // notice the change.
}
...Handle Database information
?>
...HTML CODE (THE CODE I WANT TO BE DISPLAYED)

my other thought is to just suppress the error in mysql_connect(); and leave it as it is...

$db = @mysql_pconnect(...);
HTML CODE..........

hope this helps or at least gives you an idea.