*Display values of the form inside the table on the new page

sharapov

I am generating data from database and displaying it inside input text boxes (for users to make some changes). What I need to do is when user presses "submit" button display all of the results inside the table on the new opened page. How can I do it?

Here is the example of what I am trying to do without actual data and php: http://home.pacbell.net/sharapov/form

I know that I can read the values of the submited form with the $POST or $GET, but how can I:

Open a new page with just a "menu bar" on it , (I guess I can open new page if I set target="_blank", but how can I open it with just "menu bar" showing on the page)
How can I loop through the results from $_POST to insert them inside the table.

stolzyboy

well this may help for number one problem

sharapov

stolzyboy,

By opening page like you suggesting will I be able to pass all of the variables from the form, and then pick them up with $_POST in your 'page. php'?

Thanks.

stolzyboy

yeah if you put it in an input type=button tag instead of an a tag you can post information to that page