Too Simple? Combining variables

[cli_man]

I think I am thinking to hard for this. I need to make a variable name like this:

$opt = "option_$i[$s]";

When I assign 0 to $i and $s and then echo out $opt this is what I get:

option_

If I change $opt = "option_$i[$s]"; to $opt = "option[$s]";

It works fine, but what I need is to create a array called option and loop through it several times asigning variables to it. This variable is under 2 while statements, so the value of $i changes every time it goes through the first while statement and the value of $s changes every time it goes through the other while statement so I end up with variable that look like this:

$option_0[0];
$option_0[1];
$option_0[2];
$option_1[0];
$option_1[1];

Etc, etc. Help me please, I can try to clarify what I need if you wish.

[ir4z0r]

I got this to work:

<?PHP
$option_17 = array(1,2,3);

$i = 17;
$s = 2;

${option_ . $i}[$s] = "hi";

echo $option_17[2]; // prints hi

?>

[kevinsequeira]

try this

$option_variable = "option_".$i."[".$s."]";
echo $option_variable;
$opt = ${$option_variable};
echo $opt;

reg
kevin

[cli_man]

Ok thank you kevin that was what I was looking for:
$option_variable = "option_".$i."[".$s."]";

One question though, what are the periods before and after the variables for? Thanks.

[kevinsequeira]

just a cleaner way to write the code thats all, im just seperating the text from the variable names using dot as the seperator

"option$i" is the same as writing "option".$i

the imp line there was ${$option_variable};

the ${} indicates to take the value stored by the variable name inside the {}

reg
kevin

[cli_man]

Ok now for the next stupid question, I can now asign variables in my while script and have variables like

$option_0[0];
$option_0[1];
$option_0[2];
$option_1[0];
$option_1[1];

Now I need to do an implode() on the $option_0 array, but this also is in a while statement and needs to be dynamic so how would I do that? I tried several combinations of what you gave me above and didn't get any of them to work.

So once again I can now post from one page to another the arrays but how do I tell a script how to access variable names? ex. $option_0 and $option_1

[kevinsequeira]

inside the while loop where u assign the values do this

while(// for $i){
// some code
while(// for $s){

  $option_variable = "option_".$i."[".$s."]";
   echo $option_variable;
   $opt = ${$option_variable};
   echo $opt; 

   }

$array_name_var = "option_".$i;
$array_name = ${$array_name_var};
print_r ($array_name);
}

if you want the array outside both the loops ,then do a while loop for the number for variable $i

while(//for $i){
$array_name_var = "option_".$i;
$array_name = ${$array_name_var};
print_r ($array_name);

}

this shoould do it
reg
kevin

[cli_man]

Dang your good, I was off by one period :-) That is working fine on both ends for me now and you saved me several hours of banging my head of the keyboard :-)

[cmburns69]

When doing string interpolation, "$option[$i]" is the same as $option[$i]. However, "$option$i[$s]" is the same as "$option"."$i[$s]". Since $i isn't an array, the value of $i[$s] is an undefined value.

Perhaps you should be using a two dimensional array:

$option[0][0] = "a";
$option[0][1] = "b";
$option[0][2] = "c";
$option[1][0] = "d";
$option[1][1] = "e";

for($i=0; $i<count($option); $i++)
{
    for($j=0; $j<count($option[$i]); $j++)
    {
        echo $option[$i][$j];
    }
}

// Prints "abcde"

Another solution would be to run 2 operations instead of 1:

// This code is untested, prefer to use the other way
$varname = "option_$i";
$value = "$varname[$s]";

Tom Brown
An online Starcraft RPG? Only at
http://www.netnexus.com

p.s. I know this post is late... Got distracted but left the window open!