Printing FORM variables for "thank you" page

lunchboxpad

I have a problem I hope one of you can solve. I need a real simple PHP script so that I can use a form to post some some variables, then print those variables to a "thank you" page.

Basically, I need the PHP to take the form post variables and then add them to the page, like so:

My name is $name, and I am $age. My e-mail is $email.

The script must only write the variables I include in the thank you page with the $variable. So if there are 30 variables posted, the php will only look to see which ones I want written on the page.

If anyone can do this, I would really appreciate it.

Bryan

lunchboxpad

I solved my problem. I just created a page thankyou.php and added the line below. I pointed to the thankyou.php page in my form action command.

<?php print "My name is $name, and I am $age. My e-mail is $email"; ?>

Now, when the form is posted to this php page, I get the form variables name, age, and email printed out on the page. That's just what I wanted.

Boy, PHP is much easier than PERL!!!

Bryan

Cogen

I would suggest getting in the habbit of using $POST, $GET, and $_REQUEST instead. If you use straight $name, $age, etc, then you are depending on the server to be settup a certain way. Try this instead ...

print "My name is ".$_REQUEST["name"].", and I am ".$_REQUEST["age"].". My e-mail is ".$_REQUEST["email"];

$_REQUEST will accept variables that were send using post or get.

Just a suggestion.

lunchboxpad

Cogen- Thanks for the input! I'm totally new to PHP so any help is appreciated.

Bryan

lunchboxpad

How about this.. sorry to bug!

What if I wanted to print certain things if the variable contained a value?

Say that a user did not fill in the age form field. So, I would not want the php to write the same line as if the field had input.

<IF AGE VARIABLE PRESENT>
print My name is $name, and I am $age. My e-mail is $email.

<IF AGE VARIABLE NOT PRESENT>
print My name is $name. My e-mail is $email and I don't know how hold I am!

It would need to be like if $email > 0 then print "blah, blah";

I'm not PHP writer, so I know nothing, but there would need to be some if/then so it could determine if the variable had any value.

Basically, I want to print something different if the age variable does/doesn't contain a value.

Thanks in advance!

Bryan

dinger

<?PHP
if($age == "")
{
print("My email is $email and my name is $name and I don't know how old I am.");
}
else
{
print("My email is $email and my name is $name and I am $age years old.");
}
?>

Try this for starters...

Chris

lunchboxpad

That did it! Thanks dinger!

One question, if I enter a value with an apostrophe, like the word "Owner's", it prints "Owner\'s " with a backslash in front of the apostrophe.

Can I add any code that will let a form input value of "Owner's" print out as "Owner's", rather than "Owner\'s".

Thanks.

Bryan

ucbones

Hey,

<?
$post="owner\'s";
$post=stripslashes($post);
echo "$post";
?>

Basically, the function stripslashes removes slashes added by forms from the variable you want to remove them.

Hope that helps,

ucbones