I need help!!

radical

Hello good folks!!

Please be gentle I new to php!!

I need help or advice!!

I recently installed a script on the this domain http://www.ebiz-hits.com/

But I keep getting the following error messages:-

Parse error: parse error, unexpected '=' in /home/ebizhits/web/admin/config_inc.php on line 22

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/ebizhits/web/admin/index.php on line 78

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/ebizhits/web/admin/index.php on line 82

Could anyone give me some help here on this?? Would I have to create a new database table???

Thanks in Advance to any replies
😕

stolzyboy

well the parse error can be a number of things:

missing semicolon, wrong {}'s, wrong ()'s, wrong ""'s, etc....

the others are just because the query isn't returning any results for the results functions to use

maybe start out by helping us, post some of the code where you think the parse error may be in the config.php

and the same for index.php

drag0n

or it may because of you not connecting to the mysql db correctly

Mordecai

Can we see line 22 of /home/ebizhits/web/admin/config_inc.php? There's no way to tell the problem from the information supplied.

stolzyboy

ummmm.....no.....its not because of not to connnecing to the database correctly or it would be spitting out a no connection error, his error is because he is running a function that grabs query results, but the query isn't returning anything

and yes, like I and Mordecai said, this is hard to spot with no code shown

radical

Hello Folks

This is the code for the confi_inc !

<?
function authenticate() {
global $err;
header( "WWW-Authenticate: Basic realm=\"Test Authentication System\"");
header( "HTTP/1.0 401 Unauthorized");
die($err[1]);
}

$hostnm = "localhost";
$usernm = "";

$pwd = "";
$dbName = "";

if(!MYSQL_CONNECT($localhost,$,$)){
die($err[2]);
}
if (!mysql_select_db("$auto")){
die($err[2]);
}
$query = "select * from pass where login=\"localhost".$PHP_AUTH_USER."" and pass=\"".(crypt($PHP_AUTH_PW,2))."\"";

$result = MYSQL_QUERY($query);

if((mysql_num_rows($result)!=1)or($PHP_AUTH_USER=="username")or($PHP_AUTH_PW=="password")){
authenticate();
}
@mysql_free_result($result);

$site_name="";
$admin_mail="";

$num_en=10;

$t_language= "language";
$t_user= "user";
$t_site= "site";
$t_stat= "stat";
$t_clear= "clear";
$t_cat= "cat";
$t_idu_idc= "idu_idc";
$t_idm_idc= "idm_idc";
$t_tmp_mail= "tmp_mail";

$num_rows=50;
$time_refresh=5;//sec
$time_for_stat=60;//sec

$query = "select * from ".$t_clear;

$result = MYSQL_QUERY($query);
if((mktime(0,0,0,date("m"),date("d"),date("Y"))!=mysql_result($result,0,"date"))and(date(w)==0)){
require('weekstat.php');
}
@mysql_free_result($result);

Thanks for your reply guys

nivek9991

I think the error is in this line:

$query = "select * from pass where login=\"localhost".$PHP_AUTH_USER."" and pass=\"".(crypt($PHP_AUTH_PW,2))."\"";

Try this:
$query = "select * from pass where login=\"localhost".$PHP_AUTH_USER."[/B]" and pass=\"".(crypt($PHP_AUTH_PW,2))."\"";

(Notice missing back slash after "_USER...")

Hope that helps.