how to write code for drop down event

hongmei

Hi,

I have a drop down item on my html form with several different static values. What I want to do is :

When user choose value "Other", I want to display an additional text item to allow user input. Otherwise, hide the additional text item. What kind of event-action script can I write?

Thanks for your help!

hongmei

aaron_karp

Hi,

If you want that text field to be displayed instantly as soon as the user selects "other" you'll need to use JavaScript, not PHP, since PHP can't make changes to a page without the help of your server.

If you plan to do this with PHP, once the user submits the form, you have a bit of code on the next page like this:

<?PHP
if ($_POST/GET['selectbox'] == "other") {
echo "<input name='other_text' type='text'>"
} ?>

Hope this helps...

-Aaron

hi-liter

i'm not sure if you can hide the optional text field, unless you're using lotus notes, OR want to use javascript to document.write each line dependent on the selection, and that can get busy and messy. maybe good way in js, just none that i can think of.

could disable the field, it'll show up 🙁 but least not be editable. (of course, won't work in ns4.x, but not much does):

function fieldOneDisable() {
window.document.formname.fieldOne.disabled = true;
}

//-->
</script>

Pick one:<select name="selectList" onchange=getValue();>
<option>foo1</option>
<option>foo2</option>
<option>foo3</option>
<option>other</option>
</select>

<p>

Other: <input type="text" name="fieldOne">

</form>

</body>