How do I assign the retrieved value to hidden field

[vipul73]

How do I assign the retrieved value to hidden field

<?php 
$email = $_POST["email"]; 
$db = mysql_connect("localhost", "root"); 
mysql_select_db("visitor",$db); 
$sql = "INSERT INTO invoice (email) VALUES ('$email')"; 
$result = mysql_query($sql); 
$last_id = mysql_insert_id(); 
echo "Thank you! Information entered.\n"; 

//This displays perfectly 
echo $last_id; 

//This is giving problems 
echo '<input name="lastid" type="hidden" id="lastid" value="$last_id">'; 
?> 

[sdjensen]

echo '<input name="lastid" type="hidden" id="lastid" value="'.$last_id.'">';

[kevinsequeira]

try this

echo '<input name=lastid type=hidden id=lastid value=$last_id>';

what problem is it giving, remember u need to refer to the id in the next page as lastid not last_id

reg
kevin

[vipul73]

I have tried both the methods but it is not working

[kevinsequeira]

what exactly do u mean when u say its not working ? when u view the page source for the generated page are u not able to see the value assigned for hidden variable lastid ??

reg
kevin

[sdjensen]

What is not working?

Please remember that you have to have a form around the input statement before you can retrieve it again.

[vipul73]

yeah I am having a form tag around it but the hidden field value remains $last_id and is not changed

[sdjensen]

If the following does not work, please give us the complete code for the page.

echo "<input name='lastid' type='hidden' id='lastid' value='". $last_id ."'>";