Functions

Gary_King

Example of what I want to do:

I have the following function:

function myfunction($text)
{
  print $text;
}

I want to make it, so that if $text is another variable, like $topic, then how can I make myfunction() do something else?

For instance, if I have:

myfunction($topic);

Then I want to do something along the lines:

function myfunction($text)
{
  if ($text!=$topic)
  {
    print $text;
  }
  else
  {
    print $topic;
  }
}

But of course, the preceding code will not work.

Any ideas?

sexydawg

I'm just a noob, but trying feeding the function both $text and $topic...

i.e. : myfunction($text, $topic);

Why doesn't this work?

Gary_King

Because myfunction will only accept 1 argument, from the way I created it.

diego25

Because myfunction will only accept 1 argument, from the way I created it.

But you can change it, right? Basically the problem right now is that your function needs to know about $text AND $topic as well. So either pass both variables to the functions, or do something like this:

function myfunction($text)
{
  global $text;
  if ($text!=$topic)
  {
    print $text;
  }
  else
  {
    print $topic;
  }
}

I'd prefer passing both variables, though...

Diego

Gary_King

Your solution does not work for me.

leatherback


function helpHim($request)
{
  if($request = "Your solution does not work for me.") 
  {
  echo "Why not!? What is the problem? You can't implement it in the code";
  }
  else
  {
  echo "did you try?";
 }
}

helpHim($lastpost);

Gary_King

What are you trying to say..?

leatherback

I am asking what the problem is why the solution doesn't work for you. Is it a coding problem. Doesn't it fit your current routines, or does the solution not function properly?

Gary_King

<?php

$topic="topic";

function myfunction($text)
{
  global $text;
  if ($text!=$topic)
  {
    print $text;
  }
  else
  {
    print $topic;
  }
}

myfunction($topic); // outputs nothing

?>

leatherback

I'd say you should do it like:

<?php

$topic="topic";

function myfunction($text)
{
  global $topic;
  if ($text!=$topic)
  {
    print $text;
  }
  else
  {
    print $topic;
  }
}

myfunction('blablabla'); 

?>

Since topic is the var which is not defined in the function, and is needed from the global variables.

Does tha work for you?

axo

don't forget that inside your function the variable $text is something else than the global variable $text!

unfortunately you overwrite the input-variable in your function.

function myfunction($text) {
	global $text,$topic;
	// the variable $text from input gets overwritten by the global one 
	if ($text==$topic)	{
		print $topic;
	}  else  {
		print $text;
	}
}

instead of this, you should try:

function myfunction($input) {
	global $text, $topic;
	($input == $topic) ? $foo = $input : $foo = $text;
	print $foo;
}

//test:
myfunction($topic);

should work 🙂
greets
axo

mo0ness

Gary W - do you know why you use global's and non-global's in a function? I.E:


$num1 = 6; # this is a global array assignment as it has been assigned and set *before* the function

function MyFunction($num2) # $num2 is yet to be used; however it will be used *within* the function
{
	global $num1;

if ($num1=="6")
{
	$num2 = 3+3;

	if ($num2=="6")
	{
		echo "Your numbers have been checked Ok";
	}
	else
	{
		echo "Your number were not the same!";
	}
}
}

# to call the function do: MyFunction();

From a previous post by yourslef:


<?php

$topic="topic"; # ok; $topic is a global

function myfunction($text) # Ok $text is not a global
{
  global $text;  # why is $text set as a global?
  if ($text!=$topic)
  {
    print $text;
  }
  else
  {
    print $topic;
  }
}

myfunction($topic); // outputs nothing 
# try correcting it and calling it without the $topic inside the brackets.

?>

I hope i havn't complicated things..however I think you should know this before going into functions - it is a requirement 😛.

Gary_King

Got it working now.

leatherback

Hi Gary,

Could you please makr this thread as resolved? (See link at bottom of thread).

Gary_King

I already did.