Display image from remote server

sgtpepper

Hi,

I would like to know if this is possible.....I need to display an image hosted at another website on my site. The image name is based on an Id number. The image can be located in two different directorys or may not exsist at all. So, I need to do the following with php:

If an image is found at this url - display it

<img border="0" src="http://www.XXX.com/listing_img/<? echo $row['Id']; ?>1.jpg" width="60" height="41">

If not....try to find it here

<img border="0" src="http://www.XXX.com/propImgs/<? echo $row['Id']; ?>1.jpg" width="60" height="41">

If you still dont see it...display this default image

Can you please help me with this?

Natty_Dreadlock

because u have no direct access to the harddisk, u have to open the images url and check whether it is there or not:

if($fp = fopen("http://www.XXX.com/listing_img/" . $row["Id"] . "1.jpg", "r"))
{
?><img border="0" src="http://www.XXX.com/listing_img/<? echo $row['Id']; ?>1.jpg" width="60" height="41"> 
<?php
}
else if ($fp = fopen("http://www.XXX.com/propImgs/" . $row["Id"] . "1.jpg", "r"))
{
{
?><img border="0" src="http://www.XXX.com/propImgs/<? echo $row['Id']; ?>1.jpg" width="60" height="41"> 
<?php
}
else
{
?><img border="0" src="http://www.XXX.com/propImgs/default.jpg" width="60" height="41"><?php
}

I did not test this and wrote it from the top of my head, if it does not work feel free to ask again.

sgtpepper

hmmm.....getting a parse error here...

}
else
{

kevinsequeira

remove the extra { after this

else if ($fp = fopen("http://www.XXX.com/propImgs/" . $row["Id"] . "1.jpg", "r"))

{

reg
kevin