Checking if a .gif file exists

[NeoSkullX]

Hi, guys

I have a very important problem, I need 2 check if a .gif file exist, I've used file_exists() but doesnt seem to work 😕 , does anyone know how to do this?

*the sintaxis I use is:

if(file_exists($num))
{
echo "
<center> <img src='$dirgraficas/2003.gif'> </center>
";
} else {
echo "
<center> <img src='$dirgraficas/$num'> </center>
";
}

Num has the value of 001.gif, 002.gif increments on a for() cycle

well, hope you can help me guys, cya.

[hi-liter]

never done that, but something like:

if ($_FILES['imagefile']['type'] == "image/gif") {

maybe work? i hope.

above code is from a tutorial on uploading files and restricting type allowed to be uploaded, so maybe from that it can be figured out...

here's the link to the tutorial

http://www.phpfreaks.com/tutorials/36/0.php

[NeoSkullX]

Hmm, dont think that will work, cause that only checks to c if the file is gif or not, if its not gif it doesnt do anything, what I need is 2 check if the files exists at all, 4 example:

I have the following images:

001.gif
002.gif
003.gif

007.gif
009.gif
etc...

and wanna print a message if the file doesnt exist, that my main problem.

thanx anyway

[NeoSkullX]

Hey, guys hope you can help me this is urgent. I have a school work to do and I need that little code in order 2 avoid having 2 make individual files 4 each of the missing images, wich would be very time consuming and a very big loss of space 4 all the repeated images. hope ya can help me

thanx

[batman]

Hello,

It should work with file_exists();

Try it this way:

if(!file_exists("$num")) 
{ 
echo " 
<center> I'm sorry, this picture does not exists. </center> 
"; 
} else { 
echo " 
<center> <img src='$dirgraficas/$num'> </center> 
"; 
} 

I am not sure what the problem really is. Are you getting any kind of errors you can give us?

-Blake

[NeoSkullX]

Hi, well that shows always the text message.

besides that I dont get any errors

ohh, and if I take off the "!" it works as if it didnt have the IF sentence

[Weedpacket]

Y'know, if the file is in the $dirgraficas directory, shouldn't you be looking in there to see if it exists, instead of in the directory where the script is?

if(file_exists("$dirgraphicas/$num"))
{
echo "
<center> <img src='$dirgraficas/2003.gif'> </center>
";
} else {
echo "
<center> <img src='$dirgraficas/$num'> </center>
"; 

[NeoSkullX]

nope, doesnt work 🙁

[batman]

Originally posted by NeoSkullX
Hi, well that shows always the text message.

besides that I dont get any errors

If you are getting that error message that I put up there, and not any other ones, then that means the script is working, and it can't find the file. Make sure that the file really exists manually, make sure that $num is a defined variable for it to look for, and make sure all the paths and everything are correct.

That is probably the most likely mistake.

-Blake

[NeoSkullX]

well, the main problem is not that, the thing is that most file exist and when I run the script normally (without the IF sentence) it works but shows a transparent box with a red cross in the middle if the file doesnt exist, so instead of that ugly box I wanna show my message.

[Moonglobe]

are you absolutely sure that $num is something like '001.gif', or is it just 001? try this:

if(!file_exists($dirgraphicas."/".$num.".gif")) 
{ 
echo "<center> I'm sorry, this picture does not exists. </center>"; 
} else { 
echo "<center> <img src=\"".$dirgraficas."/".$num.".gif\"> </center>"; 
}

try that, see if it works.

[Bighed]

Hi!

My question is how can I check a file if exist or not?
My homepage is on a free server.
I have a downloadable file on an other server and I'd like to check if the file exist on this server. If yes, near the file will appear a green picture, if not, a red one.

In PHP I know that there is a fuction: file_exists(), but this can check only files in the same server where the php file is.

[batman]

You could try something like this:

<?php 
$file = fopen ("http://www.bla.com/bla.htm", "r"); 
if (!$file)  

{ 
echo "<img src=\"red.gif\" height=\"10\" width=\"10\">"; 
} 
else 
{ 
echo "<img src=\"green.gif\" height=\"10\" width=\"10\">"; 
} 
?>

[Bighed]

Originally posted by batman
You could try something like this:

<?php 
$file = fopen ("http://www.bla.com/bla.htm", "r"); 
if (!$file)  

{ 
echo "<img src=\"red.gif\" height=\"10\" width=\"10\">"; 
} 
else 
{ 
echo "<img src=\"green.gif\" height=\"10\" width=\"10\">"; 
} 
?>

[/B]

It doesn't works. 😕
I always get green picture even if the file not exists.
Here is my code:

<?php

$file = fopen ("http://free.x3.hu/bighed/valami.zip", "r");

if (!$file)

{

echo "<img src=\"status_red.gif\" height=\"20\" width=\"20\">";

}

else

{

echo "<img src=\"status_green.gif\" height=\"20\" width=\"20\">";

}

?>

Something else?

[batman]

<?php 
$file = "http://free.x3.hu/bighed/valami.zip";
$fp = fsockopen ($file, 80); 
if (!$fp) 
{ 
echo "<img src=\"status_red.gif\" height=\"20\" width=\"20\">"; 
} 
else 
{ 
echo "<img src=\"status_green.gif\" height=\"20\" width=\"20\">"; 
} 
?>

Try that,

[Bighed]

I got this error message:

Warning: fsockopen() [function.fsockopen]: php_network_getaddresses: gethostbyname failed in C:\www\bighed\bighed_temp\ping\file.php on line 3

Warning: fsockopen() [function.fsockopen]: unable to connect to http://free.x3.hu/bighed/valami.zip:80 in C:\www\bighed\bighed_temp\ping\file.php on line 3

The first parameter of fsockopen() is the domain isn't it?

But how can I put in the file name?

[batman]

<?php  

$file = "http://free.x3.hu/bighed/valami.zip"; 
$fp = fsockopen ($file, 2082);  

if (!$fp)  

{  

echo "<img src=\"status_red.gif\" height=\"20\" width=\"20\">";  

}  

else  

{  

echo "<img src=\"status_green.gif\" height=\"20\" width=\"20\">";  

}  

?>

Just keep changing the # after the $file till it works. I am not sure what socket number it is.

[Bighed]

And where can I watch this number?

It's different on all server or not?

[batman]

Not sure. Try the code I posted above and see if it works with the number 2082.

[Bighed]

It isn't working. :mad: