AHH Another Problem!!

BigLinuxGeek

I'm trying to put .$_GET["whatever"]. in to a variable so I can call it into an include path, how can I put this into a variable as

$whatever=".$_GET["whatever"]."; doesnt work
nor does

$whatever=.$_GET["whatever"];

what am I doing wrong does anyone mind tell me

jerdo

Ok use $GET['whatever'] when you aren't using quotes aroung the $GET. But when you are using quotes around the $GET do it like this "$GET[whatever]". When it's inside double quotes the single quotes around the array index seem to break it.
So your examples would be:

$whatever=".$_GET["whatever"].";

Should be:

$whatever="stuff".$_GET['whatever']."stuff";

$whatever=$_GET['whatever'];

batman

This is either a mess up in the code, or you are trying to make the variable have different values. The reaon I say this is the . after the =

$whatever=.$_GET["whatever"];

If you want it to be just one variable to have one value, do it like this.

$whatever = $_GET["whatever"];

Then you have to make sure that the whatever variable is set in the url that it is calling from.

EXAMPLE:

http://www.whatever.com/hi.php?whatever=something

Then, the above url will give $whatever, the value of something.

Hope that helps,
-Blake

FrozNic

$GET["whatever"]
needs to be -> $GET['whatever'];

you can also do this:

$_REQUEST['whatever'] which i believe checks both the get and post array and pulls the value of $whatever.