Need help converting Julian date to Gregorian date

EricC

What should be a fairly straightfoward function has gotten me so twisted I'm about ready to strangle myself with my own mouse cord. 😉

I'm needing a function that will take a YYDDD format Julian date and convert it into a MM/DD/YYYY Gregorian date.

I've poured over the manuals looking at date,mktime,time and I'm at the point now I can't see the forest because of the trees. In otherwords I'm lost.

Any pointers or sample code or anything would be most helpful for my sanity. Thanks. 🙂

laserlight

You probably could use
juliantojd()
then
jdtogregorian()

EricC

I've looked at the juliantojd function, how its arguments are juliantojd(int month, int day, int year) and the data source i have to work with is in the format YYDDD which is 2 digit year and then the # of days in the year.

If I could shake the cobwebs out and figure a slick way of changing # of days to a month/day format then I'd be done with this mess.

Thanks for the reply. I'll keep poking around waiting for divine intervention. 🙂

laserlight

actually, isnt the DDD already a julian day count, except that the year isnt factored?

just factor in the year yourself and it should be ok

EricC

Just a quick note on how I finally figured out this simple problem. Sometimes I like to make things harder then they are. 🙂

Long version:

$date = "03094";
$a1 = substr($ad,2,3);
$a2 = substr($ad,0,2);
$ad = date("m/d/Y", mktime(0,0,0,1,$a1,$a2));
echo $ad
// 04/04/2003