what's wrong here?

[lorddraco98]

i have this code:

<?php
if ($_GET['action']=="" || !isset($_GET['action']))
{
$a=3;
echo "<form action= 'test.php?action=1' method= 'post'>";
$c[0]= "0";
$c[1]= "1";
$c[2]= "2";
$c[3]= "3";
$s=0;
while ($s<=$a)
{
$b=0;
echo "<input name= 'test[$b]' type= 'checkbox' value= '$c[$s]'><br>";
$b++;
$s++;
}
echo "<input type='submit'>";
echo "</form>";
}
if ($_GET['action']=="1")
{
print_r($_POST[test]);
}
?>

now on the next page, it only displays the last value of the checkbox that was checked, like if I check more than one checkbox, isn't doesn't display all the values, why is this?

[crosbystillsnas]

take the $b=0 out of the while-loop. 😉

[kevinsequeira]

view source of the form to see what the key/value pairs of the checkbox is.

and u will notice that all of them are named test[0]

so move $b=0 outside the while loop

ie change

while ($s<=$a)

{

$b=0;

to

$b=0;
while ($s<=$a)
{

also its better if u do this : instead of having this

echo "<form action= 'test.php?action=1' method= 'post'>";

use this

echo "<form action= 'test.php' method= 'post'>";
echo "<input type=hidden name=action value=1>";

and replace $GET['action'] by $POST['action']

reg
kevin

[lorddraco98]

Originally posted by crosbystillsnas
take the $b=0 out of the while-loop. 😉

that'd do it thanks, just the little things that I miss sometimes, especially in long scripts. thanks 🙂