[Resolved] Passing value of checkbox field

dleone

On one script I have the following code:

if ($row["image_2"] <> NULL)
{
    echo "\n<br><br>Image: </B>" . $row["image_2"]; 
	?><br>
	Check to delete: <input name="del_image[1]" type="checkbox">
	<br><img src="http://127.0.0.1/remains_final/photos/<?php echo $row['image_2']; ?>">
	  <br>
  <?php
}

This is part of a larger chunk the queries a DB and populates this page. The checkbox is an option that the user can check or not. This entire piece of code is within a form.
Then on the next page I use this read my variables.

 $del_image[0] = $_POST["del_image[0]"];

Using either:
empty($del_image[0]) or isset($del_image[0] )
The response is the same for if this is checked or not. It treats it as empty. I have even added value="" in the previous page where it is defined. Any idea on how to get this variable passed and evaluated??

kevinsequeira

Check to delete: <input name="del_image[1]" type="checkbox">

but in the next page u have

$del_image[0] = $_POST["del_image[0]"];

shouldnt u $del_image[1] = $_POST["del_image[1]"];

reg
kevin

dleone

Good catch, but I actually have [0] - [3] in the first and [0] only while i test the page that gets the variable. So the typo is here within my my post only.

kevinsequeira

$del_image[0] = $_POST["del_image[0]"];
Using either:
empty($del_image[0]) or isset($del_image[0] )

try this

if(isSet($POST['del_image[0]'])){
$del_image[0] = $POST['del_image[0]'];
}else{
echo "not checked";
}

print_r($_POST['del_image']);

reg
kevin

dleone

Kevin - will do, have to wait until this evening to do so. So, that I understand this correctly, the issue is that prior to getting the data, we need to see if it is set. I assume then if this does work, then replace the echo statement with setting $del_image[0] = NULL for the reset of the script to run properly.
Also, in the page where this variable is set:

should I leave it alone or add value="" or doing so, will that make isset true no matter if it is checked or not?

kevinsequeira

and

if(isSet($POST['del_image[0]'])){
$del_image[0] = $POST['del_image[0]'];
}

should work, you dont need to do anything else.

reg
kevin

dleone

Alright. you have been a lot of help throughout this entire process. In case I never mentioned this, I am redesigning my current website which is a collection of html pages and converting it to a database. (remainstobeseen.com) Also, this is serving as my master's final project in computing and information systems. Let me know if there is anything I can do to return these many favors.

dleone

I hate to say this, but it still does not work using your exact method. I have attached the two scripts for your perusal and have even modified it to spit out a variable: always outputs NO!

Only one attachment per post; will send second with next post.

dleone

Second attachment

batman

I think I found your error.

In update2 you will see a big break in the code. That's where you need to edit what I did for image 2, 3, and 4.

See attached.

dleone

Thank you Batman. I looked at the changes, but will not be able to test until tonight after work. However, I have one question: how does the value become "no" if the user doesn't check the box. As it looks now, I see that the value is "yes" and the box would be unchecked.

batman

It only will get the value "yes" if it's checked. How it sits right now, it should work.

-Blake

dleone

Don't think I am crazy: it returns NO... I think I am going crazy.

dleone

Found the error. Making 4 separate variables as opposed to an array fixed the problem...

Now instead of $del_image[], it is
$del_image_1, 2, 3, _4.

Thanks again to Kevin and Batman !!

dleone

Did this get posted:
I fixed it by killing the array and making 4 separate variables. Looks like by initializing them killed the isset funciton!