Adding line breakes!

spstieng

I have a "admin" page where a user can type in a news update.
When submitting this update, I call for a admin.php file.

In admin.php I retrieve the information typed in the previous page and store in in a variable $ni (NewsInput).

Now.... I'm putting the new input FIRST in the news file. To do that I do the follwing:

open news text file and store it using fread() into variable $old_news. Then I close the file.
Retrieve todays date, and store it into the variable $today.

Now the follwing code:

		@ $fp = fopen("data/news.txt","w");
		fwrite($fp, $today);
		fclose($fp);
		@ $fp = fopen("data/news.txt","a");
		fwrite($fp, $ni);
		fwrite($fp, $old_news);
		fclose($fp);

The problem is when I write the date to the file, it does NOT append a \n in the textfile. Neither does it do that when I append the $ni file. I've tried fwrite($fp, $today."\n") and it doesn't work - only almost. I get a weird square in my text file, and that causes problems reding the file.

:: Reading the file ::

I display the news in a table. So I read line by line, to identify if a line is a date. If it is, it goes in the left column. Other text goes in the right column.

But without the \n in my textfiles, I have text AND date on the same line - and my method doesn't understand ANYTHING.
So how can I append the "invisible" \n when writing and appending to file????

laserlight

Maybe I should suggest this:

$text = $today . "\n" . $ni . "\n" . $old_news;
$fp = @fopen("data/news.txt", "w")
	OR die("Error: could not open data/news.txt");
fwrite($fp, $text);
fclose($fp);

it is better than opening the same file twice but with different modes, since file operations are expensive.

also, what platform are you running on? the EOL character may not be "\n".

jimson

\r\n
might help in winbox.

spstieng

AHA! Windows in a nutshell! Had to use \r\n, that works. Thanks.

And thanks laserlight - it's after midnight here. Should have thought of concatinating the strings myself :-)

Now it ALMOST works......

To get the date.... I think I'm doing it the hard way....

I'm using

	$today = getdate(); 
	$month = $today['mon']; 
	$mday = $today['mday']; 
	$year = $today['year']; 
	$today = $mday.".".$month.".".$year;

The result is 12.6.2003 and im checking for 12.06.2003.
How do I get the date to add the '0' if it is below 10?

The code I'm using to see if it is a valid date, is:

if (ereg ("([0-3][0-9]).([0-1][0-9]).([0-9]{4})", $line, $regs))
{
	if (!$first)
		{  $nf = $nf."</td></tr>";  }
	if (strtotime($regs[0])) 
		then I do some stuff.....

so the ereg is (day).(month).(year) and regs[0] is the content - the date.

snaack

Originally posted by spstieng
The result is 12.6.2003 and im checking for 12.06.2003.
How do I get the date to add the '0' if it is below 10?

Easy 😃

Look: php.net strftime() function

So use something like this:

$dateFormatted = strftime("%d.%m.%Y", strftotime($dateUnformatted));

That's all 🙂

edit: fixed the link.. it's points to the dutch part of the manual though..