Checkbox values

[kattz]

Hello,
I am working on a program that allows you to select options using checkboxes, a Javascript function calculates the cost of your selections but now I need to get the selected information into the next page (after the user clicks submit options). What is the best way for me to do this? Here is some of my php code which gets the information in the first place.

echo "<tr><td><input type=\"checkbox\" name=\"selections[]\" onclick=\"calc_cost()\" value=\"$title[$i]\"></td>

<input type=\"hidden\" name=\"Cost\" value=\"$cost[$i]\">

<td>$artist[$i]</td>
<td>$type[$i]</td>
<td>\$$cost[$i]</td>

<input type=\"hidden\" name=\"Title\" value=\"$title[$i]\">
<input type=\"hidden\" name=\"Artist\" value=\"$artist[$i]\">
<input type=\"hidden\" name=\"Type\" value=\"$type[$i]\">

</tr>";

If the box is checked, I need to get this info into a table on the next page!

Any suggestions
😕

thanks in advance

[werkkrew]

I dont think a checkbox really makes use of the value="" parameter, it uses the word "selected" to say if it is already checked off upon loading...

Other then that, it behaves the same as any other form field, the name becomes the post var, that var holds a boolean value, selected or not...youd be best off doing the calculation during the processing section of the script, rather then right away because a checkbox (at least I dont think) can return any sort of value other then a boolean...

Be smart with your naming, and in the processing script, if a certain box is selected then...do this.

[laserlight]

Well, you would access the checkboxes with the $_POST array as normal.
If the checkbox is checked when the form is submitted using the POST method, it will have the given value.
Otherwise, it will not be set.

[kattz]

Can someone tell me what I am doing wrong here. I get these error messages:

Notice: Use of undefined constant select - assumed 'select' in 'blah blah'

Notice: Array to string conversion in 'blah blah'

Notice: Array to string conversion in 'blah blah'

I am trying to display the selections from page one

page one code
<input type=\"checkbox\" name=\"select[]\" onclick=\"calc_cost()\" value=\"$array\" $name[$i]</td>

and display the selections on page two in a table using

<?php
$array = $_POST[select];
for ( $loop=0; $loop<count($array); $loop++ )
{
$string = explode(",", $array);

$i = 0;
$element = $string;
$title= array($element);
$artist= array($element);
$type= array($element);
$cost = array($element);

echo "<tr><td>$name</td>
<td>$code</td>
<td>$time, $date</td>
<td>\$$cost</td>
</tr>";

}
?>

Array Array Array Array are the only values showing up in my table. What have I done wrong??????????
Ahhhhhhhhhh :eek:

[werkkrew]

you cant just have "select[]" as the name of the checkbox

youd have to use a loop to genereate the desired number of checkboxes

for($i = 0; $i < 10; $i++)
{
<input type=\"checkbox\" name=\"select[$i]\" onclick=\"calc_cost()\" value=\"$array\" $name[$i]</td>
}

or manually do it

perhaps you might even want to cut out the array and do like

<input type=\"checkbox\" name=\"select$i\" onclick=\"calc_cost()\" value=\"$array\" $name[$i]</td>

and then in the second page (this would work well if you only have a few checkboxes, otherwise it would get tedious

$selection1 = $POST[select1]
$selection2 = $POST[select2]

the way you have your loop set-up its counting the number of cells in the $_POST array, not the select array...some other things about your code dont look right, they aren wrong, but they are just a poor way of doing things