CSS in PHP

cmccomas

How/where do I include the link to a .css in the php?

Say this is the code:

<?
/* Account activation script */

// Get database connection
include 'db.php';

// Create variables from URL.

$userid = $_REQUEST['id'];
$code = $_REQUEST['code'];

$sql = mysql_query("UPDATE users SET activated='1' WHERE userid='$userid' AND password='$code'");

$sql_doublecheck = mysql_query("SELECT * FROM users WHERE userid='$userid' AND password='$code' AND activated='1'");
$doublecheck = mysql_num_rows($sql_doublecheck);

if($doublecheck == 0){
	echo "<strong><font color=red>Your account could not be activated!</font></strong>";
} elseif ($doublecheck > 0) {
	echo "<strong>Your account has been activated!</strong> You may login below!<br />";
	include 'login_form.html';
}

?>

lanjoky

1 way to do it is at the top of your script:

echo "<link href=\'test.css\' rel=\'stylesheet\' type=\'text/css\'>"

cmccomas

so,

<? 
/* Account activation script */ 

// Get database connection 
include 'db.php'; 

echo "<link href=\'test.css\' rel=\'stylesheet\' type=\'text/css\'>" 

// Create variables from URL. 

$userid = $_REQUEST['id']; 
$code = $_REQUEST['code']; 

$sql = mysql_query("UPDATE users SET activated='1' WHERE userid='$userid' AND password='$code'"); 

$sql_doublecheck = mysql_query("SELECT * FROM users WHERE userid='$userid' AND password='$code' AND activated='1'"); 
$doublecheck = mysql_num_rows($sql_doublecheck); 

if($doublecheck == 0){ 
    echo "<strong><font color=red>Your account could not be activated!</font></strong>"; 
} elseif ($doublecheck > 0) { 
    echo "<strong>Your account has been activated!</strong> You may login below!<br />"; 
    include 'login_form.html'; 
} 

?>

Nathan__02

you can also just use an include...

eg include("style.css");


<?  

/* Account activation script */  

// Get database connection 
include 'db.php';  

include 'style.css';

// Create variables from URL. 

$userid = $_REQUEST['id'];  

$code = $_REQUEST['code'];  

$sql = mysql_query("UPDATE users SET activated='1' WHERE userid='$userid' AND password='$code'");  

$sql_doublecheck = mysql_query("SELECT * FROM users WHERE userid='$userid' AND password='$code' AND activated='1'");  

$doublecheck = mysql_num_rows($sql_doublecheck);  

if($doublecheck == 0){  

    echo "<strong><font color=red>Your account could not be activated!</font></strong>";  

} elseif ($doublecheck > 0) {  

    echo "<strong>Your account has been activated!</strong> You may login below!<br />";  

    include 'login_form.html';  

}  

?>

thats the way i do it.

cmccomas

Thanks, to both of you 🙂

BIGmrC

Hiya,
I'm trying to do the same apart from I'm trying to include the .css file in side a .inc file, but i keep getting errors.

At the moment I have set folders under the www folder for different file types.
eg.
http://www.domain.com/css/
http://www.domain.com/include/
http://www.domain.com/js/

I test my code out and it works when i put the .css file in the include folder but when i put it in the css folder it doesn't work.

Can anyone help?
I just need to include the base stylesheet in the header include file.
I inculde the section stylesheet in the php file.

Thanks
BIGmrC

mrhappiness

what error do you get?
how did you try including?

BIGmrC

The code I've been trying is:

doc-start.inc

global $base_path; $base_path = "'http://localhost/webwrk/test/www/";

index.php :

<?php
include("include/doc-start.Inc");
include("include/css-start.Inc");
?>

Include/css-start.Inc :

////// or /////
<?php
include($base_path."css/style.css");
?>
///////////////

</style>

Error message :

<Br />

<B>warning</b>: failed opening 'http://localhost/webwrk/test/www/css/style.Css' for inclusion (include_path='.;C:\php4\pear') in <b>v:\apache group\apache\htdocs\webwrk\test\www\include\css-start.Inc</b> on line <b>3</b><br />

Thanks
BIGmrC