[Resolved] Im a programming wimp *help*

[Resolved] Im a programming wimp help

skinnyking

Hi,
i'd really appreciate it if one of you great 🙂 people could help me out...
Basically i'm just trying to write example programmes to bolster my php skills, BUT!
Here ive got a program which I would like a user to put a tick into a couple of checkboxes and simply output a number '1' for the first box and a '2' for the second and a number '3' if both boxes are checked, if they enter nothing at all an error message will appear. Sounds easy right?
At the moment the error is being generated when the program is run but will disappear when both are checked.....I'll get my coat.

Heres the code :

<html>
<head>
<title>Untitled Document</title>
<?php
$added = $checkbox + $checkbox2;
$var;
if(submit) {
if(!isset($checkbox,$checkbox2)) {
echo ("Enter Something!");
}
if($checkbox) {
$var=$checkbox;
}
if ($checkbox2) {
$var=$checkbox2;
}

if (isset($checkbox,$checkbox2)) {
$var=$added;
                 			 }

}

?>
</head>

<body>
<p>
</p>
<form name="form1" method="post" action="<?php echo $PHP_SELF ?>">
<input type="checkbox" name="checkbox" value=1>
option 1<br>
<input type="checkbox" name="checkbox2" value=2>
option 2 <br>
<input type="submit" name="submit" value="Submit" />
</form><br><br>
<?php
if (!isset($var)) {
echo (""); }
else echo ($var);
?>
<p>  </p>
</body>

</html>

kevinsequeira

if (isset($checkbox,$checkbox2)) {
$var=$added;
}

change to

if (isset($checkbox) AND isSet($checkbox2)) {
$var=$added;
}

and

if(!isset($checkbox,$checkbox2)) {
echo ("Enter Something!");
}

if(!isset($checkbox) OR !isSet($checkbox2)) {
echo ("Enter Something!");
}

reg
kevin

skinnyking

Sorry its still the same, the numbers will show up but the error is still generating when the prog runs.
Ive just noticed submit wasn't a variable though when it was called. Ive changed that but now the error is generating whenever submit is pressed!

Thanks for the help though.

kevinsequeira

whats the error ?

reg
kevin

kevinsequeira

<html>
<head>
<title>Untitled Document</title>
<?php
if(isSet($submit)){
  $var = "";
		if(!isset($checkbox) AND !isSet($checkbox2)) {
	  echo ("Enter Something!");
  }
		if(isSet($checkbox)){
	  $var = $checkbox;
  }
		if(isSet($checkbox2)){
	  $var=$checkbox2;
  }
 	if (isset($checkbox) AND isSet($checkbox2)) {
			$var=$checkbox+$checkbox2;
		} 
}
?>
</head>
<body>
<p>
</p>
<form name="form1" method="post" action="<?php echo $PHP_SELF; ?>">
<input type="checkbox" name="checkbox" value=1>option 1<br>
<input type="checkbox" name="checkbox2" value=2>option 2 <br>
<input type="submit" name="submit" value="submit">
</form><br><br>
<?php
if(isset($var)){
	echo $var;
}
?>
</body>
</html>

reg
kevin

skinnyking

Hey thanks! Your code simplified what I was trying to do but still didnt fix it but it made me see a mistake in the NOR condition for neither boxes checked, it should be AND:

<html>
<head>
<title>Untitled Document</title>
<?php
if(isSet($submit)){
$var = "";
if(!isset($checkbox) AND !isSet($checkbox2)) {
echo ("Enter Something!");
}
if(isSet($checkbox)){
$var = $checkbox;
}
if(isSet($checkbox2)){
$var=$checkbox2;
}
if (isset($checkbox) AND isSet($checkbox2)) {
$var=$checkbox+$checkbox2;
}

}
?>
</head>
<body>
<p>
</p>
<form name="form1" method="post" action="<?php echo $PHP_SELF; ?>">
<input type="checkbox" name="checkbox" value=1>option 1<br>
<input type="checkbox" name="checkbox2" value=2>option 2 <br>
<input type="submit" name="submit" value="submit">
</form><br><br>
<?php
if(isset($var)){
echo $var;
}
?>
</body>
</html>

Thanks again! 😃

kevinsequeira

😉 no problem, could u mark this resolved, there is a link below thanks

kevin