AGH, this is SOO simple? yet I get unexpected T_VARIABLE error!

[TylerNZ]

Ok, check my coding here:

<?php 

if ($_SERVER['REQUEST_METHOD'] == 'POST') {

if (isset($_POST['joelt'])
$joel = $_POST['joelt'] ;
else
echo "error no age data";

if ($joel < 0 && $joel > 100) {
echo "Invalid age data"; 
}

if($joel < 10) {
$total = $joel * 40;
} else {
$total = $joel * 35;
}

echo "Your TOTAL price is:" .$total;
} else {
echo "<h3>Calculate</h3> 
<form action='$_SERVER[PHP_SELF]' method='post'>
Number: <input type='text' name='joelt'><br> 
	<input type='submit' value='Submit'> 
		  </form>";
}
?>

Anyone help me see what my error is here? The Error Code is saying line 6:

$joel = $_POST['joelt'] ;

Thanks!!!

[HalfaBee]

Its a missing ) on the line before

if (isset($_POST['joelt']) )

halfaBee

[TylerNZ]

THANK YOU!!!!

geez ... one little ) .... haha

glad it's working now, also had to put some { around the 2nd if statement as well.

Thanks!!