[Resolved] even numbers

[pablodelapena]

is there a function which is capable to determine whether a number is even or odd?

[Kraft]

You can do it with a simple if statement:

if ( $variable % 2 != 0 )

What that is doing is dividing the variable by 2 and seeing if there is a remainder. The if statement should then be followed by whatever command you want to excecute of the number is in fact even.

[pablodelapena]

thanks!!🙂🙂

[WRStrong]

Question: I tried your suggestion & I get a parse error on that line.

Here's what it's for (to get a better idea):

-I have an include (oakwood-passwords.php) which has usernames/passwords in a multi-dimensional array with '$membername[$i] and $password[$i] will match up...(I know, it's not secure, but it's for a site that has VERY limited, specific viewers.

• This page is to include the oakwood-passwords.php, look at it and make the member names into a drop-down list.

• Next, it's to ask for the password.

• Upon submit, the page afterward will check to make sure that what was entered matches the included oakwood-passwords.php entry. If so, display something... if not, don't display anything.

Here's the code::

<?
include 'oakwood-passwords.php';
$totalfamilynumber = count($membername);
print
("
<form method=POST action=passcheck.php>
	<table border=1 width=40% id=table1>
		<tr>
			<td width=186>Please choose your name:</td>
		<td><select size=1 name=GivenName></select></td>
            <option selected></option>
");
print ("$membername");
for ($i = 0; $i < $totalfamilynumber; $i++)
(
if ( $i % 2 != 0 )
{
print "<option name=$membername[$i]>$membername[$i]</option>";
}
else
{
}
)
print
("         </select>
		</tr>
		<tr>
			<td width=186>Please give us your password:</td>
			<td><input type=text name=GivenPassword size=10></td>
		</tr>
	</table>
	<input type=submit value=Submit name=B1><input type=reset value=Reset name=B2>
</form>
");
?>

This one is a little confusing. If you could give me some assistance, please advise.

Thanks in advance,

B.

[TheDefender]

WRStrong, you in the right thread here?

[WRStrong]

Well, I'm not a genious; however, I thought this thread was discussing the ability to tell between even and odd . My question is exactly about that. Look at the code...

Here's the code::
<?
include 'oakwood-passwords.php';
$totalfamilynumber = count($membername);
print
("
<form method=POST action=passcheck.php>
<table border=1 width=40% id=table1>
<tr>
<td width=186>Please choose your name:</td>
<td><select size=1 name=GivenName></select></td>
<option selected></option>
");
print ("$membername");
for ($i = 0; $i < $totalfamilynumber; $i++)
(
if ( $i % 2 != 0 )
{
print "<option name=$membername[$i]>$membername[$i]</option>";
}
else
{
}
)
print
(" </select>
</tr>
<tr>
<td width=186>Please give us your password:</td>
<td><input type=text name=GivenPassword size=10></td>
</tr>
</table>
<input type=submit value=Submit name=B1><input type=reset value=Reset name=B2>
</form>
");
?>

Isn't there for and if statement in there that asks if the value of $i is even.... or odd?

At least that's what I thought. I could be wrong about it... but I highly doubt it.

If anybody has any clues, please advise.

Thanks a bunch,

B.

[TheDefender]

Yes, there is an IF that asks if it is odd, and no there are no for statements that check that. For statements are not conditional like that. I will say this though, you need curly braces, and not parenthesis after your FOR loop start...

Change:

for ($i = 0; $i < $totalfamilynumber; $i++) 
( 
if ($i % 2 != 0) 
{ 
print "<option name=$membername[$i]>$membername[$i]</option>"; 
} 
else 
{ 
} 
)

To:

for ($i = 0; $i < $totalfamilynumber; $i++) 
{ 
    if ( $i % 2 != 0 ) 
    { 
        print "<option name=$membername[$i]>$membername[$i]</option>"; 
    } 
    else 
    { 
    } 
}

Also, the if part basically checks to see if the value of $i is odd, and prints out the option, and if it isn't, then it doesn't print anything out. Given that, you can clean up the code by getting rid of the else part:

for ($i = 0; $i < $totalfamilynumber; $i++) 
{ 
    if (($i != 0) || ($i%2 != 0)) 
    { 
        print "<option name=$membername[$i]>$membername[$i]</option>"; 
    } 
}

[WRStrong]

Thanks... after a lot of tinkering & some frustration about what was wrong, I found it. I also made the code a little slicker so that it would run more smoothly.

<?
include 'oakwood-passwords.php';
$totalfamilynumber = count($NamePass);
$html = "<form method=POST action=passcheck.php>
	<table border=1 width=40% id=table1>
		<tr><td width=186>Please choose your name:</td>
        <td><select size=1 name=GivenName>
            <option selected></option>";

for ($i = 0; $i < $totalfamilynumber; $i++)
{
if ($i*.5 != floor($i*.5))
{
}
else
{
$html .= "<option value=$NamePass[$i]>$NamePass[$i]</option>\n";
}
}
$html .= "         </select>
        </td>
        </tr>
		<tr>
			<td width=186>Please give us your password:</td>
			<td><input type=text name=GivenPassword size=10></td>
		</tr>
	</table>
	<input type=submit value=Submit name=B1><input type=reset value=Reset name=B2>
</form>
";
echo $html
?>
 

In case anybody needs any help with it this way. 🙂

Take care,

B.