Question about exit statement

klycette

Here is part of the code that I'm working wih so far:

if (!$username)
{
echo "<font color=#FF0000>*</font> You must enter your username in order to gain access to your account. Please go back to the login page and provide the required information.";
exit;
}

I know that exit forces you out of php script, but the problem I'm having is with some html after this point. I have a few links that aren't echoed in php, so they're not part of the php script at all, yet they're not displayed if the user hits this exit in the script. Since exit only stops php script, I thought any html afterward would still print to the screen. I do want these links to be visible regardless of whether of not a user causes an exit to be triggered. Any thoughts?

shawon22

exit function will stop all the execution after that including html. what u could do is instead to of using exit put all ur php code inside the if statement

example:

if(!$validuser)
{
echo "goaway";
}
else
{
//all ur code goes here
}

klycette

That would help me with my problem, I don't think. In my script, I want to give error messages if they don't include their username and/or password and also if their entries don't match anything in the database. Naturally, I don't want to give them the non-match error if they didn't even enter a username...I just want to give them an error indicating that they have to provide a username. So as far as I can see, I have to use exit so further errors don't get shown, at least not until they apply. The problem is that I'd like to have links at the bottom of the page output to the screen regardless, but I don't seem to be able to do that since exit stops the entire script, not just php.

It's not a big deal, I can go without the links, as long as I have them display when no errors are triggered. If anyone has some ideas though, I'd like to hear them.