view image without true url

vbzoom_com

How can I display image using code like:
Echo "<img src='image.php?ImgNo=13'>";

I mean I want user can not know the true url of image.

leatherback

Hi,

I suppose you are worried about the user being able to save the image?
Have a look at a simultanuous thread about that problem:

http://www.phpbuilder.com/board/showthread.php?threadid=10245988

Bascially: Nope. The src="" is the location. BUT you CAN have a link like the one you mentioned. The page you link to gerenates the image, and outputs an image stream.

If in the coding of page:'image.php' you then check for certain specific elements (registered session variables, login vars etcetc) then people cannot directly link to that image from other websites. They can only get the images through your pages.

Hope that helps.

cockney

<?php
$im = ImageCreateFromJpeg("image.jpg");
Header("Content-Type: image/jpeg");
ImageJPG($im);
ImageDestroy($im);
?>

can't remember of hand if it's ImageJPG() or ImageJPEG() ..... have a look in the manual. It's up to you what you do with the query string.

vbzoom_com

this code :
<?php
$im = ImageCreateFromJpeg("image.jpg");
Header("Content-Type: image/jpeg");
ImageJPEG($im);
ImageDestroy($im);
?>

it's work without any problem but for sorry my website does not support GD . is there another way without using GD ?

Mordecai

Try using readfile() to read straight out the data from the image. You will need to set the header, most likely:
Content-type: image/PNG