Images to table

[biscutty]

I have a problem that perhaps one of you code geniouses out there could help me with...

I have want to develop a script that reads the contents of a directory for image(jpg) files and display all the images in a table, 1 image to 1 cell, then below each image I want to show the image name and a checkbox in a new cell check illustration below:

The directories all have a different number of images so the table cells need to be made for each image and image name.

I have been bashing my head at this but to no luck, here is my code below:

<?

while($entry = readdir($dir)) {
	if($entry != "." || $entry != "..")	{
	$a = $a + 1;
		if($a>"3") 
		{	echo "<tr>"; }

	echo "<td>";
	echo "<a href='$jcimages/$entry'><img src='$jcthumbs/$entry' border='2'></a>";
	echo "</td> ";

		if($a>"3") 
		{	echo "<tr>"; $a='1'; }
	}}

	?>

As you can see I am far off, but any help would be much appreciated..

thankya

[eduard]

something like this :

$intImgCounter = 0;
while ($file = readdir($dir)){
  if (($file != ".") && ($file != "..")){
     $intImgCounter++;
     if ($intImgCounter == 1){ print ("<tr>\n"); }
     print ("<td><img src=\"$file\"></td>\n");
     if ($intImgCounter >= 4){ print ("</tr>\n"); $intImgCounter = 0; }
  }
}

[freedomsam]

Originally posted by eduard
something like this :

$intImgCounter = 0;
while ($file = readdir($dir)){
  if (($file != ".") && ($file != "..")){
     $intImgCounter++;
     if ($intImgCounter == 1){ print ("<tr>\n"); }
     print ("<td><img src=\"$file\"></td>\n");
     if ($intImgCounter >= 4){ print ("</tr>\n"); $intImgCounter = 0; }
  }
}

[/B]

How about...

if ( eregi(".jpg$","$file") )

instead of...

if (($file != ".") && ($file != ".."))

This will only pick up files that end in ".jpg" or ".JPG". Otherwise, you will try to display files that aren't JPG, if any exist in the directory.