[Resolved] Dropdown box selection

[gabriel]

How do I create a dropdown box in PHP that will show a list of images from a directory of images? And also how do you get the path to the images including the image name to automatically show up for the value of the option in the dropdown box?

[daimoore]

I am not to sure what you are exactly after but think this may be it:

$imagepath1 = "c:/dir/......."
$imagepath2 = "c:/dir/......."
$imagepath3 = "c:/dir/......."

<SELECT name="dropdown1">
<OPTION value=" <?php $imagepath1?> "><?php echo "imagename1"?> </OPTION>
<OPTION value=" <?php $imagepath2?> "><?php echo "imagename2"?> </OPTION>
<OPTION value=" <?php $imagepath3?> "><?php echo "imagename3"?> </OPTION>
</SELECT><BR>

note that i have put the image name in php tags obviously you do not need to do this, unless you were using variables to identify the image name.

You could also you a 'for each' loop to cycle through each element in the dir. But don't worry about that if you do not know how to do that.

Is this what you meant?

[gabriel]

I think I have figured it out, all I did was:

<?php
$handle=opendir('images/');
echo"<select size=\"1\" name=\"D1\">";
while ($file = readdir($handle)) {
if ($file != "." && $file != "..") {
echo "<option value=\"images/$file\">$file</option>";
}
}
echo "</select>";
closedir($handle);
?>