Wont show my echos

nistka93

I am tring to get this to work, but all it shows is a blank page.

if ($sweep == "cash") {
if ($cat[0] == "cash" or $cat[1] == "cash" or $cat[2] == "cash" or $cat[3] == "cash" or $cat[4] == "cash" or $cat[5] == "cash" or $cat[6] == "cash" or $cat[7] == "cash") {

echo ("<font size=4><a href=\"" . $row['url'] . "\" target=\"_top\" onmouseover=\"window.status=\'" . $row['site'] . "\'\;return true\;\" onmouseout=\"window.status=\' \'\;return true\;\">" . $row['name'] . "</a>");
echo ($row['entry'] . "  |  " . $row['age'] . "  |  <a href=\"" . $row['rulesurl'] . "\">Rules</a>");
echo ("  |  " . $country . "</font><br>");
echo ("<table bgcolor=#C0C0C0><tr><td>" . $row['description'] . "</td></tr></table>");
echo ("Ends: " . $row['ends'] . "<p> </p>");}}

Can you have a if statement inside another one? Could that be whats wrong?

Any help is greatly appreciated. Thanks in advance.

snoopy13

you can have an if statement inside an other - that wount be the problem.
I'm only guessing, but probably it's the $row thing. where do you get this array from? is it possible, that there is a mistake in the code?

Weedpacket

My suspicions would have me looking at $sweep and $cat - they're the variables controlling the if statements, after all; if $row was bad then there'd still be stuff echoed. Do they have the values they're supposed to? [man]var_dump[/man] is your friend in these; it will tell you what's inside a variable, what type of thing it is, whether it's an array or a string or whatever...

The two ifs can be combined into one that would probably be a lot easier to read

if($sweep=='cash' && in_array('cash',$cat))
{

...and of course there'd only be the one } to finish the statement. It does of course assume that $cat[0]..$cat[7] is the entire $cat array.

Nixon

Have you tried using the print command? Also space out your code, give it space to breathe because it makes it a LOT easier to read.

jimson

u might want to change ur coding style.... my IMHO.

http://www.phpbuilder.com/board/showthread.php?s=&threadid=10234388

nistka93

I tried the in_array command like you said, now I get this error...

Wrong datatype for second argument in call to in_array in /users/iwebland.com/lotzacash/sweeps.php

$cat is defined using this code...

$cat = unserialize(urldecode($row['catagory']));

$row is called as a row from a mysql table

I attached the whole file if anyone would like more clearity as to what I am tring to do.

Also, Is there a way to display all the data in a array without calling each possible cell?

Weedpacket

That tells me $cat isn't even an array; I'm guessing that $row['catagory'] contains a serialised array of categories - why do you urldecode() it? Is it urlencoded when you store it?

Did you var_dump($cat) like I suggested, to see what it contained?

nistka93

I tried the var_dump($cat); and it gave me bool(false)

Yes , $row['catagory'] is urlencoded when I store it. That was suggested to me in

http://www.phpbuilder.com/board/showthread.php?s=&threadid=10247130

What maybe happening is when the data is stored there could be only 1 variable in the array, if that happens, is it still an array?

Sorry to be such a pain.

jimson

What maybe happening is when the data is stored there could be only 1 variable in the array, if that happens, is it still an array?

if(is_array($yourData)) {
     echo "is array";
} else {
     echo "not array";
}

Weedpacket

Originally posted by nistka93
I tried the var_dump($cat); and it gave me bool(false)

That's telling me that unserialize() failed because it didn't get proper serialised data (possibly because it was mangled by the urldecode()) - as the manual says "In case the passed string is not unserializeable, FALSE is returned.".

What do the contents of $row['catagory'] look like?