combo box select problem

[zuzupus]

<? foreach($hprojekt as $value) { ?>
<option value="<?= $value ?>" <? if ($HTTP_POST_VARS['projekt'] == $value){ echo "SELECTED";}?>><?= $value ?></option>
<? } ?>
project_00 //default selected value
project_01
project_02
project_03

when i choose project_02 and subit the form then im getting project_02 as selected

this works fine but when i login for next time im getting project_00 as default is it possible to get slected one as default one ,when login for next time

thanks in advance

[trooper]

Right well your code is looking for a value in the $_POST['projekt'] so when you login again unless you have actually made a POST to that page then it will default to the first one

Sounds like you are not actually POSTING anything to the page

HTH

GM

Originally posted by zuzupus
<? foreach($hprojekt as $value) { ?>
<option value="<?= $value ?>" <? if ($HTTP_POST_VARS['projekt'] == $value){ echo "SELECTED";}?>><?= $value ?></option>
<? } ?>
project_00 //default selected value
project_01
project_02
project_03

when i choose project_02 and subit the form then im getting project_02 as selected

this works fine but when i login for next time im getting project_00 as default is it possible to get slected one as default one ,when login for next time

thanks in advance

[zuzupus]

sorry i couldnt understood what $_post as i used $HTTP_POST_VARS ..hopefully yuw will be clarify by giivng any example as im totally newbie in pgmming

thanks

[kevinc]

Yeah, I think you're a little confused with your variable use here. $_POST will only work from FORM postings, with method="POST" in your form definition.

If you're wanting this to work EVERY time that page is accessed, defaulted to the last chosen value, you're going to have to store a cookie on the users machine, or, alternatively, if this is behind an authentication section, have a field in the user's unique row, called last_selected or whatever, and every time that form is received, you update that value with the "last selected value."

Then, when you're wanting to mark one as selected, use $SESSION instead of $POST, or, the $Var used for the database communication.

Hope this helps.

Kevin.

[zuzupus]

sorry it still not working

if (isset($HTTP_POST_VARS["date"]))
{
$nr = $SESSION["nr"];
$datum = $SESSION["date"];
$von = $_SESSION["test"];
}
to get session stored values when user login every time but its not workign in this way

<? if (!isset($SESSION["Save"])) { ?>

<? if ($SESSION['projekt'] == $value)

still im not able to figure out.sorry for your inconvenience

regards

[kevinc]

Well, obviously $_SESSION['projekt'] is going to have nothing it int, you haven't registered a session by that name.

Follow this basic example :

print "
<SELECT name='number'>
";
for($i=0;$i<10;++$i) {
   if($_SESSION['number'] == $i) {
 print "
   <option SELECTED value='$i'>$i</option>
";
} else {
 print "
   <option value='$i'>$i</option>
";
}
}
print "
</SELECT>
";

Okay, now, we'd still receive $POST['number'] ... then we'd say $SESSION['number'] = $_POST['number'].

Bear in mind, this is using SESSIONS. You need to use $_COOKIE for storage once the browser has been closed.

Hope it helps.
Kevin.