Take Content From MySQL Table

[Paris_Holley]

i want to be able to set the variable

$updates =

then have it equal like a certain row/column in a certain table in a mysql database.....

so on the site if i put $updates if will load that content from the mysql table and place it on the site

[Kinsbane]

<?php
$conn=mysql_connect(host, user, pass);
$sql_db=mysql_select_db(database,$conn);
$sql="SELECT col1, col2";
$sql_result=mysql_db_query($sql_db,$sql_quer);
$sql_array=mysql_fetch_array($sql_result);
$colum1=$sql_array['col1'];
$colum2=$sql_array['col2'];
?>

<table><tr><td><? echo $col1; ?></td></tr>
<tr><td><? echo $col2; ?></td></tr></table>

should be about right.

[Paris_Holley]

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home2/pixella/public_html/connect.php on line 6

[Paris_Holley]

this is what i had i put -- instead of the actually info

<?
$conn=mysql_connect(--,--,--); 
$sql_db=mysql_select_db(--,$conn); 
$sql="SELECT --"; 
$sql_result=mysql_db_query($sql_db,$sql_quer); 
$sql_array=mysql_fetch_array($sql_result); 
$colum1=$sql_array['--']; 
?> 
<table><tr><td><? echo $col1; ?></td></tr> 

is it because the variable $sql_query was not defined?

[Paris_Holley]

nevermind i got it