[Resolved] function using array

jassh

ok.. hi there everyone..

here's my problem...
my function doesnt seems to generate the name using array
as i think it should.. (i was hoping it would 🙂 )
i'm quite puzzled over this one...
so can anyone point out what seems to be the problem??

function generate($name, $age) {

echo $name;
echo "<BR>";
echo $age;
echo "<BR>";
echo "---------<BR>";

}

$name_array = array ('me','myself','and','Irene');
$age_array = array ('23','23','23','21');

generate($name_array, $age_array);

thanks in advanced;
-jassh

tasistro

Must loop through elements like this...

for ($counter=0;$counter<count($name);$counter++) {
echo $name[$counter];
|
echo "<BR>";

tuf-web_co_uk

your not using the same variables in your function compared to the rest of your script

your function is looking for $name and $age your giving it $name_array and $age_array

and secondly your not loading the array correctly

u want $name[0] not $name, as this doesnt tell php the part of the array you want to load

<?
function generate($name, $age) { 
for($i=0;$i<4;$i++ ) {     

echo $name[$i]; 
echo "<BR>"; 
echo $age[$i]; 
echo "<BR>"; 
echo "---------<BR>"; 
}     

} 

$name = array ('me','myself','and','Irene'); 
$age = array ('23','23','23','21'); 

generate($name, $age);

?>

ybinds

Well, I think the names of the parameters can differ with the array names. That should not make any difference. The problem is that he is not using the loop to display the elements, which I guess he must have solved by now.

jassh

loops... damn!! :rolleyes:
yeah.. i thought so...
but here's the actual example which i follow the thing from.
and it didnt show any type of loop..
which interest me in the first place...

function create_table($data){

echo "<table border='1'>";
reset($data);
$value = current($data);

while ($value) {
echo "<tr><td>$value</td></tr><br>";
$value = next($data);
}
echo "</table>";

$my_array = array('One', 'Two', 'Three');
create_table($my_array);

now, this work, without having to use the 'for' Loops

anyone can explain why???

thanks in advanced.

cheers;
-jassh

feldon23

There are a million ways to traverse an array.

I think next(); is a rather primitive way because you can't tell where you are.

Instead of all that current/reset stuff, let's look at some modern PHP. Replace:

reset($data); 
$value = current($data); 

while ($value) { 
echo "<tr><td>$value</td></tr><br>"; 
$value = next($data); 
}

with:

foreach ($data as $value) {
  echo "<tr><td>{$value}</td></tr><br>"; 
}

Realize that if you have $name and you do:

$name = array('elvis', 'jonah', 'michael');

then the value of $name is meaningless.

echo $name;

will give you:

Array[]

echo $name[0];

will give you:

elvis

jassh

whoaa... thanks dude...
now.. my eyes are getting clearer...
thanks for all the guidance..
u guys are great!!!!

as usual.. i will proudly click the [RESOLVED] button 😃

cheers;
-jassh