Text file and variables

saeed42

I have text file and a basic script that reads it, my question is how can I place variables in the text file, which then can be replaced with a value which is passed from a form.

My intention is to have a form where a user will select few options and then after the submission the script will read a text file, which I'm using as template, depending on the selection the script will open the appropriate text file and then place the users data into the variables in the text file and the whole lot would be printed onto the screen

Thanks in advance

TTT

http://fi.php.net/eval

HalfaBee

You may want to look at http://www.php.net/str_replace or http://www.php.net/preg_replace as well.

HalfaBee

saeed42

I'm still not sure how to do this so I think it's time for an example.

Let's say I have a script that reads a file "test.txt"

<?
$name = "Saeed";
$file = fopen("test.txt", "r");
$reading = fread($file, 3000);
eval("$reading");
print (nl2br($reading));
fclose($file);
?>

and the test.txt file has one line which is my name is $name, my question is how do I get the script to replace "$name" variable with the value that it's set to.

Thanks in advance😃

HalfaBee

You are very close.
eval()'s confuse the hell out of me sometimes 🙁

HalfaBee

<? 
$name = "Saeed"; 
$file = fopen("test.txt", "r"); 
$reading = fread($file, 3000); 
print nl2br(eval("return $reading")); 
fclose($file); 
?>

saeed42

When I do that I get the following error msg

Parse error: parse error, unexpected T_STRING in E:\Site\master\reading.php(11) : eval()'d code on line 1

Thank you for getting back to me so promptly

HalfaBee

try eval "return \"$reading\"; "

HalfaBee

You have to imagine the string being eval()ed as a line of php.

HalfaBee

saeed42

Still getting the same error msg with

print nl2br(eval("return \"$reading\"; "));

HalfaBee

Try

echo "return \"$reading\";"; before the eval and see what comes out.

It may give you a clue as to what is happening.

HalfaBee

saeed42

That prints the content including "$name"

HalfaBee

Cut and paste the output from the echo and post it.
$name should be in it, not the replacement.

Maybe put
echo "return \"$reading\";";
to define what it is returning.

HalfaBee

saeed42

print out is

my name is $name ";

HalfaBee

What is missing from what I posted, Monkey?

HalfaBee

saeed42

Excuse me ?

HalfaBee

If you do not see, you will never learn Monkey.

I posted
Maybe put
echo "return \"$reading\";";
to define what it is returning.

You relpyed

print out is

my name is $name ";

What is wrong with this?

Halfabee