[Resolved] $REMOTE_ADDR; inside a function

[spighita]

Hello:
When I define a variable for example:

function adduser(){

$ipuser=$REMOTE_ADDR;
echo $ipuser;
}

Notice: Undefined variable: REMOTE_ADDR in C:\www\this.php on line 66

Why?
.
Thanks in advance for anyone who helps.

[cgraz]

You most likely have error reporting set to all and need to access that variable as if globals were off.

Change it to

$ipuser = $_SERVER['REMOTE_ADDR'];

Although, I wonder why you're creating a whole new variable.

Why not just do

echo $_SERVER['REMOTE_ADDR'];

Saves you a step.

Cgraz

[spighita]

I want to enter the user's ip into a database. Then use it along the script, I'm working with a switch and many functions.

It worked fine, thank you.

😃

[spighita]

I also found another way of doing it.

$ipuser=$REMOTE_ADDR;
function adduser()   {
     global $ipuser;
     echo $ipuser;
}

[Paragon]

I dont know exactly what your using it for. I got this to work tho.

Filename : anything you want

<form action="test.php" method="POST">
  <input id="username" name="username" type="text" size="15">
  <BR>
  <BR>
  <input id="password" name="password" type="password" size="15">
  <BR>
  <input id="user_ip" name="user_ip" type="hidden">
  <BR>
  <input name="submit" type="submit">
</form>

Filename : test.php // or just change the action in the form

<?php
$username = $_POST['username'];
$password = $_POST['[password'];
$user_ip = $_SERVER['REMOTE_ADDR'];

echo "$username";
echo "<BR>";
echo "$password";
echo "<BR>";
echo "$user_ip";
?>