Passing the var..

pinehead18

Ok here is my setup. I have a file called functions.inc which houses all my php statements.

When someon logs in at login.php login.php then has the function userlogin(); If i put he code strait on to login.php it works....

However if i have it reference the function from functions.inc ... It doens't pass the variables so $uname turns into nothing.

How do i do that?

Do need to use something like $GET or $post?

DeltaRho2K

Post your function here, so we can see exactly what you are trying to do with it... It just sounds like you aren't passing the variable into the function properly or even at all...

pinehead18

$db = mysql_select_db("pinehead", $con) or die(mysql_error());
$sql = "SELECT * FROM users where uname='$uname' and pass='$pass'";
$result = mysql_query($sql);
$row = mysql_fetch_array($result);

    if ($row["uname"] == $uname && $row["pass"] ==

$pass) {
setcookie ("user", "cookie", time()+604800);
echo "you are now logged in";
} else {
echo "Incorrect login";

}

that is my function.;.
Thank you
Anthony

Pig

sounds like uname and pass are not being transferred. You have to either global the user and pass (bad idea) or pass them with the function call.

You did not give us the top of the script, so I cannot tell if you have something set up to do this. Anyway, you would want to call the script like this:

userlogin($pass, $user);
NOT: userlogin();

pinehead18

When i do userlogin($uname,$pass); it says unable to find functino.. Even though the function name is userlogin

Pig

double check to make sure you have included the correct file and that the function is declared properly.

DeltaRho2K

On your login.php page prior to calling the function, add the following:

// Set the variables to pass them into the function.
$uname = $_POST['uname'];
$pass = $_POST['pass'];

// Echo them both to make sure the values exist (for debugging purposes only.  Remove later if it passes them properly.)
echo $uname.", ".$pass;

Of course, this assumes you are using the POST method to pass the variables...

pinehead18

do i put that inside the function { } or do i put that on the same page i'm using userlogin($pass,$uname); ??

DeltaRho2K

Put this on the page you are calling the function from (I assume it is login.php based on your first post.)

Then right below it, make a call to your function like so:

userlogin($uname,$pass);

pinehead18

OK quick question for you becuase this isn't making a whole lot of since.

That works great btw.. it will pass $pass all the way and work even when i echo it. However it wont pass $uname; i have loginbox.php login.php and functions.inc when i echo $pass and $uname on login.php it echo's them both.. When i echo it in the functions page with the code it only echos $pass.. When i set userlogin($pass); it will work. when i set userlogin($uname) even though login.php will echo the contents of $uname it wont work. And when i do userlogin($pass,$uname); only $pass will echo.

Any ideas?
Thanks
Anthony