How do I include files in different directories using include()

[lupercal]

I have used the following code on one of my scripts causing it to break.

I am using require() in file_A to call file_B which calls file_C using the code below

include ('../file_C.php');

why is this. The path is correct. And this works when file_B call file_C

However when file_B is called by file_a it can no longer call file_C correctly.

I believe I am specifying the path to the included file incorrectly because when I move file_C to the same directory and use .

include ('connect_test.php'); within file_B

everything works correctly. But what am I doing wrong

[paulnaj]

Are all the files in the same directory? If not, let us see your file/folder structure.

Remember, when file_B is inserted into file_A using include/require, the 'scope' of file_B's code is still file_A.

So, suppose you have a file structure as follows: ...

file_A.php
php/file_B.php
php/file_C.php

... and ...

In file_A, you call include "php/file_B.php".
In file_B, you call include "file_C.php".

1) If you run file_B.php independently, it will succeed in finding file_C.php. (File-scope is file_B.php)

2) If you run file_A.php, it will find file_B.php OK.
BUT, the scope for the code in file_B.php is that of file_A.php (because the code is run in file_A) so it won't find the reference to file_C.php in file_B.php.

Now, the command in file_B.php that would work for example (2) is include "php/file_C.php", even though that line WOULD NOT WORK if file_B.php is run independently of file_A.php.

Hope that makes sense!!

[lupercal]

thankyou for your help

[paulnaj]

No problem!

Remember to mark the thread as resolved once you've found the answer you're looking for.

P.