[Resolved] how to use if statement? In this scenerio

[sgtpepper]

I am display three images if the name is in a db. Sometimes, it may not be in the database. I need to know how I can display images only if a name is available.

Would this be some sort of if statement? Here is what I am doing and it displays broken images, (with red X) if the file does not exsist.

<?
//Picture1
?>
                      <a href="http://www.xxx.net/propimages/featured/<? echo $row[Idf]; ?>/<? echo $row[picture_name];?>" target="_blank"> 
                      <img border=0 src="http://www.xxx.net/propimages/featured/<? echo $row[Idf]; ?>/<? echo $row[picture_name];?>" width="78" height="57"> </a> 
<?
//picture 2
?>
                      <a href="http://www.xxx.net/propimages/featured/<? echo $row[Idf]; ?>/<? echo $row[picture2_name];?>" target="_blank"> 
                      <img border="0" src="http://www.xxx.net/propimages/featured/<? echo $row[Idf]; ?>/<? echo $row[picture2_name]; ?>" width="78" height="57"> 
                      </a> 
<?
//picture 3
?>
                      <a href="http://www.xxx.net/propimages/featured/<? echo $row[Idf]; ?>/<? echo $row[picture3_name];?>" target="_blank"> 
                      <img border="0" src="http://www.xxx.net/propimages/featured/<? echo $row[Idf]; ?>/<? echo $row[picture3_name]; ?>" width="78" height="57"> 
                      </a> 

[Pig]

You need to do the if around the entire <img> tag, not inside the tags

if( $row[whatever] != NULL )
{
echo("<img src=$row[whatever]");
}

[sgtpepper]

This works very well...thank you...one quick question....what if I wanted to add the width height.

Doing this breaks it..

<?
if( $row[picture2_name] != NULL )
{
echo("<img src=http://www.xxx.net/propimages/featured/$row[Idf]/$row[picture2_name]" width="85" height="48");
}
?>

Sorry for such a newbie question

[sgtpepper]

Never mind....got it...dumb mistake