include and required not parsed

saeed42

I have a php script that creates a template page everything was Ok until I decided I should have a header page and include that into the script so whenever I want to change anything I can just change the header file, my problem now is instead of getting header page I get <?php require('/Header/header.php'); ?> at the beginning of every page and it doesn't get parsed.


  print ("<?php require('/Header/header.php'); ?>\n");
  echo "<BR><BR><BR><BR><BR><BR>";
  echo "<H2>$title $dir</H2>\n";
  echo "<table width='80%' border='0' align='center' cellpadding='2' cellspacing='2' bgcolor='#EBEBEB' class='Tblborder'>  \n";
  echo "<TR bgcolor='#FFFFFF'>\n";
  echo "<TD bgcolor='#FFFFFF' WIDTH='30'>&nbsp;</TD>\n";
  echo "<TD><FONT COLOR=0000FF>Name</FONT></TD>\n";
  echo "<TD ALIGN=RIGHT WIDTH='120'><FONT COLOR=0000FF>Size &nbsp;&nbsp&nbsp</FONT></TD>\n";
  echo "<TD WIDTH='200'><FONT COLOR=0000FF>Description</FONT></TD>\n";
  echo "</TR>\n";
  echo "</TABLE>\n";
  echo "<BR>";
  echo "<TABLE  width='80%' border='0' align='center' cellpadding='2' cellspacing='2' bgcolor='#EBEBEB' class='Tblborder'>\n";

hkucsis

<?php require('/Header/header.php'); ?>

is enough, no need to add print at the beginning.

saeed42

When I do that it doesn't parse anything but the include command,
it just prints everything else just like they are i.e. echo " ";

mzanimephp

What version of PHP are you using? Can we see your whole page?

saeed42

I'm using version php-4.2.2-17.2 with Apache 2.0.40-21.3 on Red Hat 9.0,
the code is more than 200 line, are you sure you want me to post it