$variable = required(filename)

[saeed42]

I was just wondering if it's possible to set variable to the output of include file.

The included file needs to be parsed.

echo "<PRE>";
$reading = require("templates/800temp-confg");
echo "</PRE>";}

//Write the config to a new file 
$writefile = fopen($refname, w);
          fwrite($writefile, $reading);
	fclose($writefile);

The above script only writes 1 to the file instead of parsing the
included file and then writing the output to a new file

[_e_r_k]

ob_start();
require("templates/800temp-confg"); 
$reading = ob_get_contents();
ob_end_clean();

//Write the config to a new file 
$writefile = fopen($refname, w); 
fwrite($writefile, $reading); 
fclose($writefile);

[saeed42]

Thank you ever so much it does almost everything, now I just have to figure out how to replace <BR /> with carriage return

I think this will do the job

$reading = str_replace("<br />","\r" ,$reading) ;

[saeed42]

One problem, everything seems to work on my windows development machine, but when I uploaded all to my Linux box the script only produces a blank file, I changed the permissions of the directory to 777 to no avail

[saeed42]

Thanks, it works just fine