help with uploads

[pablodelapena]

Hey, im wanting to make a hting which allows users to my site upload images to the server to a certain directory.

Is there anyway i can do this while also checking a few other things:
a)image is a jpeg or gif
b)under a certain size, e.g 10Kb
and c) rename it to a variable of my choice??

how would i do this? or who can tell me where i can learn a bit more about uplaoding.

php.net hurt my brain when i searched for this.

[boxfresh]

Post to upload.php using a form with a file field called imageFiles[].
e.g.

<form enctype="multipart/form-data" action="upload.php?upload" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="30000">
Send this file: <input name="imageFiles[]" type="file">
<input type="submit" value="Send File">
</form>

Here is the upload script i use.
If there is a URL variable called upload the script will be executed

upload.php

[PHP CODE]

if(isset($REQUEST["upload"]))
{
$ftp_server = "xxx.xxx.xxx.xxx";
$username = "ftpusername";
$password = "ftppassword";
$public_dir = "public_html/graphics/"; // the webroot or the place where you want to move the file.
$source = $FILES['imageFiles']['tmp_name'][0];

//this is where you chode the destination filename
$destination = ('test_tn.jpg');

$conn_id = ftp_connect($ftp_server); 

// login with username and password
$login_result = ftp_login($conn_id, $username, $password); 
// check connection
if ((!$conn_id) || (!$login_result))
{ 
	echo("FTP connection has failed!");
    echo("Attempted to connect to $ftp_server for user $ftp_user_name<br>"); 
    die; 
}
else
{
	echo("Connected to $ftp_server, for user $username<br>");
}


// upload image
$upload = ftp_put($conn_id, $public_dir."/".$destination, $source, FTP_BINARY);
// check upload status
if (!$upload)
{ 
echo "FTP upload to $ftp_server has failed!";
}
else
{
echo "Uploaded $source to $ftp_server as $destination<br>";
}

// close the FTP stream 
ftp_quit($conn_id); 

}

[/PHP CODE]

you can find out various info on the uploaded file using the following:

$_FILES['userfile']['name']
The original name of the file on the client machine.

$_FILES['userfile']['type']
The mime type of the file, if the browser provided this information. An example would be "image/gif".

$_FILES['userfile']['size']
The size, in bytes, of the uploaded file.

$_FILES['userfile']['tmp_name']
The temporary filename of the file in which the uploaded file was stored on the server.

$_FILES['userfile']['error']
The error code associated with this file upload. ['error'] was added in PHP 4.2.0

You also need to ensure your hosting allows file uploads, in my experience there are quite a few that don't

I hope this helps you.

[stolzyboy]

it's all pretty much right here

http://www.php.net/manual/en/function.move-uploaded-file.php

and here

http://www.php.net/copy

[pablodelapena]

you are my hero boxfresh! few blips! but i can iron those out! thanks!

[pablodelapena]

ok, i can connect no problem, but its telling me now that the file or directory doesnt exist! when it quite blatantly does.

here i my edited version.

<?php

$ftp_server = "ftp.example.com"; 
$username = "user103"; 
$password = "password"; 
$public_dir = "var/www/html"; // the webroot or the place where you want to move the file. 
$source = $_FILES['imageFiles']['tmp_name'][0];
$user = "pablo";

//this is where you chode the destination filename 
$destination = ('$user.jpg'); 

$conn_id = ftp_connect($ftp_server); 

// login with username and password 
$login_result = ftp_login($conn_id, $username, $password); 
// check connection 
if ((!$conn_id) || (!$login_result)) 
{ 
echo("FTP connection has failed!"); 
echo("Attempted to connect to $ftp_server for user $ftp_user_name<br>"); 
die; 
} 
else 
{ 
echo("Connected to $ftp_server, for user $username<br>"); 
} 


// upload image 
$upload = ftp_put($conn_id, $public_dir."/".$destination, $source, FTP_BINARY); 
// check upload status 
if (!$upload) 
{ 
echo "FTP upload to $ftp_server has failed!"; 
} 
else 
{ 
echo "Uploaded $source to $ftp_server as $destination<br>"; 
} 

// close the FTP stream 
ftp_quit($conn_id); 



?>

is it possible to sue a variable in the $destination = ('$user.jpg'); line?

[boxfresh]

you'd have to do it like this:

$destination = $user.".jpg";

you don't actually need the parentheses either.

Cheers

[pablodelapena]

ok, great! now im getting an error opening on line 31??

im not used to ftp, so excuse my noobiness!

[boxfresh]

you may need to chmod your var\www\html directory to allow the script to write to it.

Depending on your version of PHP you may need to use $HTTP_POST_FILES instead of $_FILES

I'm not sure which is the most recent.

[pablodelapena]

grat, thanks, ill work something out, cheers for all your help though!