Date help

luckybob

I want to run a check on the current date with a date I have store in my database. I have worked out a snipit of code to test this by using the date() and mktime() functions. I basicly convert the stored date with mktime(), then I convert the current time by calling the date() and using the output in the mktime(). This returns comparable information, but my variables rollover to -1. How can I prevent this, or is there a better way?

Here is the code:

...
$month = date("m");
$day = date("d");
$year = date("y");
$hour = date("h");
$minute = date("i");
$seconds = date("s");

$timestamp = mktime($month,$day,$year,$hour,$minute,$seconds);

$currentime = mktime(date("m"),date("d"),date("y"),date("h"),date("i"),date("s"));

echo "\nTimetstamp = $timestamp ";
echo "\nCurrent Time = $currentime";

if ($timestamp == $currentime)
{
echo " Victory is Mine!";
}
...

I tried comparing the time() with the mktime() using the date and I get different times. Any help is appreciated.

Thanks,
Luckybob

irwa82

Hi,

Below is a sample script I wrote for you. $OldDate would be the mktime value from the database. I pasted an old one the to show that it is not the same date.

If you have any questions then please ask.

kind regards,
Anthony Irwin

<?php
$OldDate = date("d/m/Y", "1016608321");
$Today = date("d/m/Y", mktime());

echo "Old Date: " . $OldDate;
echo "Today: " . $Today;

if ($OldDate != $Today) {
echo "Dates do not match";
}
else {
echo "Dates do match";
}

luckybob

Hey, Thanks for the code. I think it will work for what I need. I would like to know how this works. I understand the date() function, but what does putting the mktime() in the date function do? If you wouldn't mind explaining that part, I would appreciate it.

Weedpacket

Originally posted by luckybob
Hey, Thanks for the code. I think it will work for what I need. I would like to know how this works. I understand the date() function, but what does putting the mktime() in the date function do? If you wouldn't mind explaining that part, I would appreciate it.

It probably doesn't do anything: it will return the current time, because you're not specifying anything else, but the current time is what date() will use if you don't have a second argument at all.

luckybob

OK, I tried the code and it works, but not for what I have, or mabye I don't know how to make it work. I am getting this data from the user:

month, day, year, hour ,min, sec

I want to convert that to a time() based int to evaluate. I also want to beable to display the date using the int provided. When I do this now, date("d/m/y h:i:s", "1844255643"), does not show the date when I use a number created by time().

Here is my code:

//this is how I get the initial value
$start = mktime($mon,$day,$year,$hour,$minute,$seconds);
$stop = mktime($mon2,$day2,$year2,$hour2,$minute2,$seconds2);

//This is how I save it in my database, but when I call on it I use this
$strt=date("m/d/y h:i:s",$start);
echo($strt);

$stot=date("m/d/y h:i:s",$stop);
echo($stot);

This does not show the correct time entered initialy. So my question is, how do I make it acurate?

tekky

did you read the the mktime() help?

its not mktime(mon, day, year, hr, min, sec) its mktime(hr, min, sec, mon, day, year)

luckybob

Ok, that will do it. I can't believe i missed that. I have been racking my brain over it. I figured the way I was doing it was fishy, but I looked at the mktime() and just thought, "It is smart enough to figure it out". and left it at that.

But I do appreciate the help.

Luckybob