Printing an image link and passing variable?

Tim_L

Hi,

I figured out that the code to print a text link which will pass my variable to the next page is:

print"<a href=\"write_review.php?PID=$product_id\">Write 
                    Review</a>";

My question is: How would I write an image link? I've tried various things but it just doesn't want to do it for me and gives me a parse error?

Thanks...

zingbats

My question is: How would I write an image link?

Do you mean like to a .jpg or .gif file? Or from an image created within a database or one where the image URL Is in the database and you need to go to that.

Sounds confusing but you should know which one u need.

Tim_L

Sorry - I wasn't very clear!

I meant instead of a text link, I'd have a picture (like a button pic) as the link which users can click on to get to the next page. Instead of a boring old text link!

Is this clearer?

steadyguy

Just place the appropriate <img> tag in the place of the text you have there now:

Tim_L

The only thing is that I need to PRINT it in PHP to pass the variable to next page.

I tried what you said but I get a parse error and I've checked it for syntax errors.

Could anyone write the short PHP code for me so that the PHP PRINTS or I suppose it could also ECHO it?

steadyguy

I was giving you the general gist, not the PHP code ... that would look something like this:

print '<a href="write_review.php?PID=' . $product_id . '"><img src="yourPicture.jpg" alt="Write a Review" width="50" height="12" /></a>';