[Resolved] [Resolved] arsort problems

sunilj20

Hello people,

I am using the arsort function for string my array.
Before sort my array looked like this
$myarray

Array ( [0] => 0 [1] => 0 [2] => 7 [3] => 0 [4] => 0 [5] => 0 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15] => 0 [16] => 0 [17] => 0 [18] => 0 [19] => 0 [20] => 0 )

After i run

arsort($myarray)
reset($myarray)

i get a sorted array which looks like this :
Array ( [2] => 7 [1] => 0 [10] => 0 [3] => 0 [4] => 0 [5] => 0 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [0] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15] => 0 [16] => 0 [17] => 0 [18] => 0 [19] => 0 [20] => 0 )

Which is not what i want. The error here is that the positions of [10] => 0 and [0] => 0 get interchanged.

What am i doing wrong??

Regards
Sunil Jambekar:mad: :mad:

bad76

Hi,
I think nothing is wrong.
arsort() function sort the value in array in reverse order and maintain index association. But this not means that keys are sorted too...

To do this you have to use a custom sort function.

For more info look www.php.net/usort

see you

sunilj20

Well if you see the array
Array ( [0] => 0 [1] => 0 [2] => 7 [3] => 0 [4] => 0 [5] => 0 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [10] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15] => 0 [16] => 0 [17] => 0 [18] => 0 [19] => 0 [20] => 0 )

apart from [2] => 7 rest all elements have the value of 0. So in a way what i want is to have [2] => 7 to come first in the result and the rest of the order as same.

Array ( [2] => 7 [1] => 0 [10] => 0 [3] => 0 [4] => 0 [5] => 0 [6] => 0 [7] => 0 [8] => 0 [9] => 0 [0] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15] => 0 [16] => 0 [17] => 0 [18] => 0 [19] => 0 [20] => 0 )

What is not clear is that [2] => 7 comes 1st but it swaps the position of [0] => 0 and [10] => 0.

Last option for me is to write a manual sorting function for the same.

Please let me know.
Thanx & Regards

Sunil Jambekar

bad76

Originally posted by sunilj20
What is not clear is that [2] => 7 comes 1st but it swaps the position of [0] => 0 and [10] => 0.

I think this happens as result of sort internal operation. If you put a "1" into 13 or other array's position, i think you'll get another result (and not only 13 at second place, but even other misplaced number...).

this is what i'm getting:

Array ( [2] => 7 [13] => 1 [12] => 0 [14] => 0 [11] => 0 [16] => 0 [18] => 0 [17] => 0 [10] => 0 [15] => 0 [9] => 0 [4] => 0 [3] => 0 [1] => 0 [5] => 0 [6] => 0 [8] => 0 [7] => 0 [0] => 0 )

If you want also sorting for key, i think your only way is to use usort(). I'm sorry.

sunilj20

Originally posted by bad76

If you want also sorting for key, i think your only way is to use usort(). I'm sorry.

I am not sorting for key. I am only sorting for value. But i want the values to maintain index associations.

Thanx & Regards

Sunil Jambekar

bad76

Originally posted by sunilj20
I am not sorting for key. I am only sorting for value. But i want the values to maintain index associations.

If so, what is wrong in your first post?
You're saying that "0" and "10" are swapped. But this is a sort by key, isn't right?

I understand you want sort by value, for equals value sort by key.

To do this you have to make your own function.

sunilj20

Originally posted by bad76

To do this you have to make your own function.

Rightly said .... write yor own function.
Thats the only way out for me it seems 🙁🙁

Thanx for all your help.

Sunil Jambekar