passing form vars

zoobie

I think there must be a better way to do this. The user selects an image from a drop-down box on a previous page which is previewed on the page below. Problem is, I have to make several "if" this option and "if" that option scripts to cover all options...Couldn't I somehow just pass the var (selected image) into the proper slot within just one general script? Below is what I'm using now. Thanks

<?php
if($_POST["img"] == "kiss") {
echo "<html>
<head>
<title>Preview</title>
</head>
<body bgcolor='#000000' style='overflow:auto'>
<table align='center' cellpadding='5' cellspacing='5' width='85%'>
<tr><td align='center'><img src='img/kiss.gif'></td></tr>
</table>
</body>
</html>";
}

if($_POST["img"] == "heart") {
echo "<html>
<head>
<title>Preview</title>
</head>
<body bgcolor='#000000' style='overflow:auto'>
<table align='center' cellpadding='5' cellspacing='5' width='85%'>
<tr><td align='center'><img src='img/heart.gif'></td></tr>
</table>
</body>
</html>";
}

etc, etc...

feldon23

if(!is_empty($_POST['img'])) {
echo "<html>
<head>
<title>Preview</title>
</head>
<body bgcolor='#000000' style='overflow:auto'>
<table align='center' cellpadding='5' cellspacing='5' width='85%'>
<tr><td align='center'><img src='img/{$_POST['img']}.gif'></td></tr>
</table>
</body>
</html>";
}

Weedpacket

Though you'd still want to check to make sure that they didn't submit img="something stupid".

Have an array of all the legitimate names, e.g.

$imgs = array('kiss', 'heart', [i]etc.[/i]);

And modify the if to read

if(!empty($_POST['img']) && in_array($_POST['img'], $imgs))

The rest as feldon23 suggests.

zoobie

FATAL ERROR: Call to undefined function: is_empty()

I used isset() which seems to work...I have never seen is_empty and assumed it was predefined...

Thanks

paulnaj

It's a typo ... should be just empty($var), not is_empty($var).