Variable variables -- very confused

jkpolsar

If you could help me out, it'd be great.

Basically, I'm trying to create a script that checks the values of a submitted forum, where the number of fields are dynamically created with a while loop (user selects from 1-10).

Each value is...
<input type="file" name="file_1">
<input type="file" name="file_2">
etc... , depending on how many fields the user decides to select.

screen_number is a hidden input on the page that stores the number (1-10) that the user has selected.

On the next screen, I want to create a while loop to check to see if the values of the dynamically created form are filled in.

The latest version of it is this...

if ($action == "upload") {
$num = "1";
while ($num <= $screen_number) {
$sourcefile = { "file_" . $num };
$$sourcefile = $sourcefile;
if (!isset($sourcefile)) {
$file_check = "0";
}
$num++;
}

[more code]

}

which gives a parse error, and wouldn't work anyway even if it didn't give a parse error 🙁

I need "$sourcefile" to be set as a variable "$file_1", "$file_2", etc, but NOT the value of the that variable... the value will be from the form.

If that doesn't make sense, it's basically a dynamic version of this

if (!isset($file_1)) {
$file_check = "0";
}

Thank you!

majik-sheff

A better method for you to use would be to have the page return an array.. instead of having your HTML look like this:
<input type="file" name="file_1">
<input type="file" name="file_2">
etc..

make it look like this:
<input type="file" name="file[1]">
<input type="file" name="file[2]">
etc..

Then when you are checking values in your script, you can use the EACH function to step through the array.

jkpolsar

Thank you, everything's working now 😃

HalfaBee

Further on variable variables.

if ($action == "upload") {
    $num = "1";
    while ($num <= $screen_number) {
        $sourcefile =  "file_" . $num;
        if (!isset($$sourcefile)) {
            $file_check = "0";
        }
        $num++;
    }
}

Would have worked as well.

Halfabee