Regular Expression: hot to detect 'è' 'ò' chars

[fabiuz]

Hi,

I am trying to detect and filter this chars but I still didn't find the solution :-(

Could anybody help ?

The code I am using is:

$find = array("/((\w|[é])+)(\s*)(,|.)/", "/((\w|[é])+),{1})((\w|[é])+)/", "/(!{1}|\?{1}|.{1})((\w|[é])+)/");
$change_with = array("\1\3", "\1 \2", "\1 \2");

echo preg_replace($find , $change_with, $text_box);

What I want to get is:

hallo...my name is,peter --> hallo... my name is, peter
(add spaces after .)

hallo!Welcome --> hallo! Welcome
(add space after !)

hallo ,world --> hallo, world
(move spaces)

perchè,così --> perchè, così
(add space after comma detecting 'è' char also)

\w seems not to include such chars, I am testing on PHP 4.2

Thank you very much

[Weedpacket]

Instead of (\w|[é]), try ([\wé]) - that would probably be simpler. (And while I was typing that, I realised: make sure it really is é and not é!) Whether \w matches é or not depends on your system's locale settings, which can be altered by using [man]setlocale[/man].

Let's see. \b - which matches "word breaks" - is probably not the best choice for spotting boundaries between word and non-word characters, because "-" is a non-word character. This paragraph is an example of the problems one would face about whether spaces should or should not follow or precede hyphens.

Any of [!.?,:;] that is immediately followed by a word character (\w or [\wé]) should have a space inserted after it

$text = preg_replace("[!.?.:;](?>[\wé])", "$1 ", $text);

Commas should not be preceded by spaces

$text = str_replace(' ,',',',$text);