PHP version of Mysql's 'like'

lazzerous

I am looking for a way to take a document that has specific pieces of information that are partially unique and modify them...

this sounds somewhat simple, but most people haven't seen the output of Quark's 'Express Tags'

basically, if there's something like
<*p(#,#,#,#,#,#,g,"US English")>

but everything within the parenthesis is unique, and I want to take some of the data within and use it elsewhere...

this is all very confusing... anyone have any ideas?

Thank you in advance for your support
-=Lazzerous=-

superwormy

Regular expressions / strstr() function sounds like what you're looking for...

www.php.net/strstr
www.php.net/stristr

www.php.net/preg_match
www.php.net/ereg
www.php.net/eregi

lazzerous

Kind of the direction I'm going, but not exactly. Let me clarify ( I rarely giove enough info upfront... sorry)

I want to look for "<p(%)>" or maybe "<ra(%)*p(%)>"
where % could be anything

is there a better solution to do this?

Thanks again
-=Lazzerous=-

lazzerous

ok... I have ym data figured out a little better... i hope this comes out making sense...

Each line of data starts with '<' or '@'

each line is seperated by a carriage return

here is an example of one of the lines:
<ra(1,0,K,100,0,0,75%)p(0,0,0,9,0,0,g,"U.S. English")><*t(5.354,0,"1 "25.242,0,"1 "65.782,0,"1 "109.381,0,"1 "134,1,"1 "190,1,"1 "246,1,"1 "300,1,"1 "357,1,"1 "409,1,"1 "460,1,"1 ")> A +.015" B +.010" B<->1 <-U>+.005" <k20> <k$> C +.005" D +.010" <k-20> <k$>D<->1 <-U>+.010" <k20> <k$>E +.010"

all I need to do is seperate these lines into three parts
the first part being everything like this:
"<%>" or "@%:"
("%" represents unique data that will change from line to line)

the second part is everything in that line after that until
<%>, which is the third part

does that make sense?

Thanks mucho
-=Lazzerous=-

lazzerous

another correction

all of the small tags (, <->, etc) would already be replaced before i get to this part - those dont have unique data

Weedpacket

superwormy's suggestions still hold: preg_match() would be your best bet. Not understanding the description of the format I can't really write an expression.