thanks for ur sincere advice and support for this post it alomost solved but when i add second field name uvorganag then it causing trouble when i enter any value in this field then its adding in drop down as well as adding empty space in first and second drop down,a wierd result
plz have a look for more clear what im trying to covince
http://server2.vitodesign.com/scripts/drop.phtml
if anybody help me out in this matter will be very helpful to mr as djerratik is in holiday till friday 🙂 and im not coming tomorrow
only on monday
thanks in advance
<? include("../settings.php");
/* Connecting, selecting database */
$link = mysql_connect("$dbhost", "$dbuser", "$dbpw")
or die("Could not connect");
mysql_select_db("$dbuser") or die("Could not select database");
if (isset($HTTP_POST_VARS['hadd'])){
mysql_query("INSERT into emp_details SET hvorgang = '".$HTTP_POST_VARS['newhvorgang']."'");
echo "added: ".$HTTP_POST_VARS['newhvorgang']."";
}
if (isset($HTTP_POST_VARS["hremove"])){
mysql_query("DELETE from emp_details WHERE hvorgang = '".$HTTP_POST_VARS['hvorgang']."'");
}
/***if i remove these code then it works fine for h vorgang***/
if (isset($HTTP_POST_VARS['uadd'])){
mysql_query("INSERT into emp_details SET uvorgang = '".$HTTP_POST_VARS['newuvorgang']."'");
echo "added: ".$HTTP_POST_VARS['newuvorgang']."";
}
if (isset($HTTP_POST_VARS["uremove"])){
mysql_query("DELETE from emp_details WHERE uvorgang = '".$HTTP_POST_VARS['uvorgang']."'");
}
/*** **************************************************** ***/
$query = "SELECT hvorgang,uvorgang FROM emp_details ";
$result = mysql_query($query) or die("Query failed: $query");
$getrow= mysql_fetch_array($result);
$hvorgang = array();
$uvorgang = array();
while ($row = mysql_fetch_assoc($result))
{
array_push($hvorgang, $row["hvorgang"]);
array_push($uvorgang, $row["uvorgang"]);
}
$haupt = array_unique($hvorgang);
$unter = array_unique($uvorgang);
?>
<html>
<head>
<title>Beschreibung</title>
<link rel="stylesheet" type="text/css" href="../styles/styles1.css" />
<script language="JavaScript" src="../JS/editdropdown.js"></SCRIPT>
</head>
<body leftmargin="0" topmargin="0" marginwidth="0" marginheight="0" bgcolor="#666666">
<?
?>
<body>
<form name="theForm" action="" method="post">
<TR bordercolor="#FF6600">
<TD nowrap>Enter Option Name:
<input type="text" name="newhvorgang">
<select name="hvorgang">
<option value="">Option List</option>
<? foreach($haupt as $value) { ?>
<option value="<?= $value ?>" <? if ($HTTP_POST_VARS['hvorgang'] == $value){ echo "SELECTED";}?>><?= $value ?></option>
<? } ?>
</select>
<br>
<input type="submit" value="Add Item" name="hadd">
<input type="submit" value="Remove Item" name="hremove"> </TD>
</TR> <br><br>
<!--if i remove this table uvorgang then it works normal for above table -->
<TR bordercolor="#FF6600">
<TD nowrap>Enter Option Name:
<input type="text" name="newuvorgang">
<select name="uvorgang">
<option value="">Option List</option>
<? foreach($unter as $value) { ?>
<option value="<?= $value ?>" <? if ($HTTP_POST_VARS['uvorgang'] == $value){ echo "SELECTED";}?>><?= $value ?></option>
<? } ?>
</select>
<br>
<input type="submit" value="Add Item" name="uadd">
<input type="submit" value="Remove Item" name="uremove"> </TD>
</TR>
</form>
</body>
</html>